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Vinil7 [7]
3 years ago
15

Yolo has 2 pieces of string. One is 32 inches long, the other is 48 inches long. She wants to make as many necklaces as she can,

all of the same length. What is the longest necklace that can be made?
Mathematics
2 answers:
olasank [31]3 years ago
8 0

Answer:

8 Inches

Step-by-step explanation:

If she cuts the 32 inch string into strands of 8 inches then she will have 4 equal pieces. And since 48 is divisible by 8 as well, this would mean 8 inches would have to be the longest necklace she'd be able to make.

32/8= 4 strands of 8 inches

48/8= 6 strands of 8 inches

Tema [17]3 years ago
8 0

Answer:

8

Step-by-step explanation: For this question we should just find the greatest common factor between 32 and 48 since we want the necklace to be as long as it can be but still have equal pieces. Meaning, no fractions.

If you had 32 inches of string you could make four 8 inch long necklaces since there in no other factor greater than 8 that can be divisible by both of these numbers. With a string 48 inches long, you can make 6 8 inch long necklaces. That would be a total of 10 necklaces betweenn 80 inches of string (between both pieces)

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Suppose that you measure a pen to be 10.5cm long. Convert this to meters.
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Una torre de 28.2 m de altura esta situada a la orilla de un rio, desde lo alto del edificio el ángulo de depresión a la orilla
Svet_ta [14]

Answer:

El ancho del río es 59.9 metros.

Step-by-step explanation:

El ancho del río lo podemos calcular con la siguiente relación trigonométrica asumiendo que la torre forma un triángulo rectángulo con el río:

tan(\theta) = \frac{CO}{CA}

En donde:

CA: es el cateto adyacente = Altura de la torre = 28.2 m

CO: es el cateto opuesto = ancho del río =?

θ: es el ángulo adyacente a CA

Dado que el ángulo de depresión (25.2°) está ubicado fuera de la parte superior de la hipotenusa del triángulo que forma la torre con la orilla opuesta del río, debemos calcular el ángulo interno (θ) como sigue:

\theta = (90 - 25.2)^{\circ} = 64.8 ^{\circ}

Ahora, el ancho del río es:

CO = tan(\alpha)*CA = tan(64.8)*28.2 = 59.9 m

Por lo tanto, el ancho del río es 59.9 metros.

Espero que te sea de utilidad!                  

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E=mc^2 in terms of m
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In 2002, the Centers for Disease Control and Prevention (CDC) reported that 8% of women married for the first time by their 18th
ehidna [41]

Question:

In 2002, the Centers for Disease Control and Prevention (CDC) reported that 8% of women married for the first time by their 18th birthday, 25% married by their 20th birthday, and 76% married by their 30th birthday. Based on these data, what is the probability that in a family with two daughters, the first and second daughter will be married by the following ages? (Enter your answers to four decimal places.) (a) 18 years of age (b) 20 years of age (c) 30 years of age

Answer:

A.) 0.0064

B.) 0.0625

C.) 0.5776

Step-by-step explanation:

Given the following :

Married by 18th birthday = 8% = 0.08

Married by 20th birthday = 25% = 0.25

Married by 30th birthday = 76% = 0.76

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P(First daughter will be married by 18) = 0.08

P(second daughter will be married by 18) = 0.08

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B.)

P(First daughter will be married by 20) = 0.25

P(second daughter will be married by 20) = 0.25

P(1st and 2nd married by 20) = (0.25×0.25) = 0.0625

C.)

P(First daughter will be married by 30) = 0.76

P(second daughter will be married by 30) = 0.76

P(1st and 2nd married by 30) = (0.76×0.76) = 0.5776

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