Answer: E. Greater than 10
Step-by-step explanation:
First, know that number to the left of a number line are negative and the square of any negative number will be positive and a perfect square.
Since the square of the unknown number is less than 1/100 i.e 0.01 then the possible unknown number 'n' can be -0.01 itself, of which the square of -0.01 will give us 0.0001 (1/10,000) i.e a value less than 0.01.
The reciprocal of 1/10000 is 10,000 which is a value greater than 10.
The annual salary of Mrs. Fredrick is $ 39397.2
<u>Solution:</u>
Given, Mrs. Frederick is paid semimonthly.
Her semi-monthly salary is $1.641.55.
Now, let us find her monthly salary first.
<em>monthly salary = 2 x semi – monthly salary </em>
So, monthly salary = 2 x 1,641.55 = $ 3283.1
Since there 12 months in a year, we obtain the annual salary as follows:
Now, the<em> annual salary = 12 x monthly salary </em>
Annual salary = 12 x 3283.1 = $ 39397.2
Hence, the annual salary of Mrs. Fredrick is $ 39397.2
Answer:
20 photos
Step-by-step explanation:
4 photos per page, 5 pages. 4 x 5 is 20.
Step-by-step explanation:
The Taylor series expansion is:
Tₙ(x) = ∑ f⁽ⁿ⁾(a) (x − a)ⁿ / n!
f(x) = 1/x, a = 4, and n = 3.
First, find the derivatives.
f⁽⁰⁾(4) = 1/4
f⁽¹⁾(4) = -1/(4)² = -1/16
f⁽²⁾(4) = 2/(4)³ = 1/32
f⁽³⁾(4) = -6/(4)⁴ = -3/128
Therefore:
T₃(x) = 1/4 (x − 4)⁰ / 0! − 1/16 (x − 4)¹ / 1! + 1/32 (x − 4)² / 2! − 3/128 (x − 4)³ / 3!
T₃(x) = 1/4 − 1/16 (x − 4) + 1/64 (x − 4)² − 1/256 (x − 4)³
f(x) = 1/x has a vertical asymptote at x=0 and a horizontal asymptote at y=0. So we can eliminate the top left option. That leaves the other three options, where f(x) is the blue line.
Now we have to determine which green line is T₃(x). The simplest way is to notice that f(x) and T₃(x) intersect at x=4 (which makes sense, since T₃(x) is the Taylor series centered at x=4).
The bottom right graph is the only correct option.
