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3 years ago

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Mathematics

1 answer:

Nataly_w [17]3 years ago

6 0

Answer:

The answer is B both players have 1/4 of chance of winning so it is a fair game

Step-by-step explanation:

You might be interested in

Find S18 for geometric series given a5=-6 and a2= -48

Ganezh [65]

an = a1r^(n-1)

a5 = a1 r^(5-1)

-6 =a1 r^4

a2 = a1 r^(2-1)

-48 = a1 r

divide

-6 =a1 r^4

---------------- yields 1/8 = r^3 take the cube root or each side

-48 = a1 r 1/2 = r

an = a1r^(n-1)

an = a1 (1/2)^ (n-1)

-48 = a1 (1/2) ^1

divide by 1/2

-96 = a1

an = -96 (1/2)^ (n-1)

the sum

Sn = a1[(r^n - 1/(r - 1)]

S18 = -96 [( (1/2) ^17 -1/ (1/2 -1)]

=-96 [ (1/2) ^ 17 -1 /-1/2]

= 192 * [-131071/131072]

approximately -192

3 0

3 years ago

3. Find all the zeroes of the equation,

Nady [450]

Answer:

djdjdjeueueuududhfh ch by by CV

7 0

2 years ago

Consider the table showing the given, predicted and residual values for a data set.

nadezda [96]

Hi friend,
D) (4, 0.1)
Hope this helps you!

4 0

3 years ago

Read 2 more answers

30. 3 x (5 + 6) = 33 33. 14 - (8 - 2) - 1 = 36. (3 + 2) × (4 + 6) = 39. 6 x 4 + 5) =

Vanyuwa [196]

Answer:

39. 29

36. 50

33. 7

30. 33

Step-by-step explanation:

39. According to the Order of Operations, in this case, Subtraction & Addition are evaluated after Division & Multiplication:

$6 \times 4 + 5 = 24 + 5 = 29$

36. Evaluate everything since everything is wrapped in parentheses:

$(3 + 2) \times (4 + 6) = 5 \times 10 = 50$

33. Evaluate everything inside of parentheses FIRST:

$14 - (8 - 2) - 1 = 14 - 6 - 1 = 7$

I am joyous to assist you anytime.

7 0

3 years ago

As part of a new advertising campaign, a beverage company wants to increase the dimensions of their cans by a multiple of 1.10.

Firdavs [7]

Answer:

New can holds $112.25\,\,cm^3$ more than the old can

Step-by-step explanation:

Given: Diameter of the can is 6 cm and height is 12 cm such that volume of can is $339.12\,\,cm^3$

Dimensions of the can are increased by a multiple of 1.10

To find: Difference between the volume of new can and volume of old can

Solution:

Volume of can (v) = $339.12\,\,cm^3$

Let r, h denote radius and height of the can.

Let R, H denotes radius and height of the new can.

r = diameter/2 = $\frac{6}{2}=3\,\,cm$

h = 12 cm

R = $3(1.1)=3.3.\,\,cm$

H = $12(1.1)=13.2\,\,cm$

New volume (V) = $\pi (R)^2H=\pi(3.3)^2(13.2)=451.37\,\,cm^3$

So,

$V-v=451.37-339.12=112.25\,\,cm^3$

7 0

3 years ago