It is too blurry i will try too help if I tell me what too do
The measure of the central angle is 89.95 degree or 1.57 radians if the radius of the circle is 7 cm.
<h3>What is a circle?</h3>
It is described as a set of points, where each point is at the same distance from a fixed point (called the centre of a circle)
We have a length of an arc of a circle of radius 7 is approximately 10.99 cm.
The radius r = 7 cm
The arc length l = 10.99 cm
We know,
l = rθ
θ is the central angle.
θ = l/r = 10.99/7 = 1.57 radians
To convert 1.57 radians into the degree multiply it by 180/π
θ = 89.95 degree
Thus, the measure of the central angle is 89.95 degree or 1.57 radians if the radius of the circle is 7 cm.
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It’s is 1)
A black kid black white white shirt with green green red black
Answer:
m∠B ≈ 51.5°
Step-by-step explanation:
A triangle solver can find this answer simply by entering the data. If you do this "by hand," you need to first find length BC using the Law of Cosines. Then angle B can be found using the Law of Sines.
<h3>Length BC</h3>
The Law of Cosines tells us ...
a² = b² +c² -2bc·cos(A)
a² = 21² +13² -2(21)(13)cos(91°) ≈ 619.529
a ≈ 24.8903
<h3>Angle B</h3>
The Law of Sines tells us ...
sin(B)/b = sin(A)/a
B = arcsin(sin(A)×b/a) = arcsin(sin(91°)×21/24.8903)
B ≈ 57.519°
The measure of angle B is about 57.5°.
Resolving horizontally . Make forces to the right positive
resultant force = 70cos30-60cos60 = 60.62-60 = 0.62 lbs
resolve vertically
resultant force = 120 sin60 - 70 sin30 = 103.92 - 35 = 68.92 lbs in downward direction
magnitude of the ressultant forsse = sqrt(68.92^2 + 0.62^2) = 68.92 lbs
direction of the force = tan-1 (0.62 / 68.82) = 0.52 degrees east of south or
a bearing of
90 - 0.52 = 89.48 degrees
