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3 years ago

What is the Greatest Common Factor of the two monomials? 15a²b, 35ab2

Mathematics

1 answer:

m_a_m_a [10]3 years ago

8 0

Answer:

5ab

Step-by-step explanation:

To find the greatest common factor (GCF), you will need to find the largest value that both of these monomials can be divided by. There are three different parts to these monomials: the number value, variable a, and variable b.

Find the largest number of each element that can be divided by both.

Numbers: the GCF of 15 and 35 is 5 (15/5 = 3, 35/5 = 7, 3 and 7 are prime numbers and therefore, cannot be divided further)

Variable a: the GCF of a² and a is a

Variable b: the GCF of b and b² is b

Therefore, the GCF is 5ab.

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Plz help ibzcbiscibscibaciv

lisov135 [29]

Answer:The answer is 2 if you use a calculator.

Step-by-step explanation:

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3 years ago

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lapo4ka [179]

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2 years ago

Factorize x^2/16+xy+4y^2

lisov135 [29]

Answer:

$\frac{x^2}{16} +xy+4y^2$ can be factored out as: $(\frac{x}{4} +2\,y)^2$

Step-by-step explanation:

Recall the formula for the perfect square of a binomial :

$(a+b)^2=a^2+2ab+b^2$

Now, let's try to identify the values of $a$ and $b$ in the given trinomial.

Notice that the first term and the last term are perfect squares:

$\frac{x^2}{16} = (\frac{x}{4} )^2\\4y^2=(2y)^2$

so, we can investigate what the middle term would be considering our $a=\frac{x}{4}$ , and $b=2y$ :

$2\,a\,b=2\,(\frac{x}{4}) \,(2\,y)=x\,y$

Therefore, the calculated middle term agrees with the given middle term, so we can conclude that this trinomial is the perfect square of the binomial:

$(\frac{x}{4} +2\,y)^2$

4 0

3 years ago

Please simplify this expression ! Show your work and please answer this !!

tangare [24]

Answer:

18q^2 - 52q + 32

Step-by-step explanation:

We can use the Distributive Property to solve this.

(2q-4)(9q-8)

2q(9q) + 2q(-8) + -4(9q) + -4(-8)

18q^2 - 16q - 36q + 32

18q^2 - 52q + 32

18q^2 - 52q + 32

6 0

3 years ago

Need help quick please. Find the area of the sector use 3.14 for pi

olga55 [171]

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2 years ago