Answer:
Where is the question?
Step-by-step explanation:
please attach it...
Answer:
32°
Step-by-step explanation:
Given:
∠DMQ = 58º
In this circle, the radius is DM. Since AD is tangent to the circle M, at point D, and the angle between a tangent and a radius is 90°
Therefore, ∠MDQ = 90°
The total angle in a triangle is 180°. Since we have the values of ∠MDQ and ∠DMQ, ∠DQM will be calculated as:
180 = ∠DMQ + ∠MDQ + ∠DQM
Solving for ∠DQM, we have:
∠DQM = 180 - ∠DMQ - ∠MDQ
∠DQM = 180 - 90 - 58
∠DQM = 32°
The measure of ∠DQM is 32°
Answer:
Step-by-step explanation:
Asymptotes 3
g(x) = 
Factors of denominator will be,
x² - 3x - 10 = x² - 5x + 2x - 10
= x(x - 5) + 2(x - 5)
= (x + 2)(x - 5)
Therefore, factored form of g(x) will be,
g(x) = 
Asymptotes 4
h(x) = 
= 
= 
= 
10x = 4(2x -9)
10x = 8x - 36
10x - 8x = -36 - 8x
2x = -36
2x ÷ 2 = -36 ÷ 2
x = -18
If you need a better explanation just as in the comments.
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There are many ways to do this.
One way could be 0.25x+7.00=27