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cluponka [151]
3 years ago
10

Please help are you to do is find the surface area of the pyramid please help please

Mathematics
2 answers:
Delvig [45]3 years ago
7 0

Answer:

180.286868 or 180.29

Step-by-step explanation:

28 X 8.7 = 243.6

243.6 x 1/2 = 180.29

Hunter-Best [27]3 years ago
6 0

Answer:

ok

Step-by-step explanation:

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How do I do problem number one
jolli1 [7]
So you have to find something that multiples to six but also somehow either subtracts or adds to five. So I would pick 2 and 3 because two plus three is five. Then you would write out your equation
X2+2x+5x+6
This may not be the way your teacher taught however it is much easier for me to do it this way.
5 0
4 years ago
Sherry has a package in the shape of a rectangular prism. What is the volume, in cubic inches (in.), of the rectangular prism? (
Rudiy27

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete as the dimension of the prism is not given. However, the following steps can serve as a guide for you.

The volume of a rectangular prism is calculated as thus:

Volume = Length * Width * Height

So, Take for instance

Length = 2\ in

Width = 3\ in

Height = 4\ in

The Volume would be:

Volume = 2\ in * 3\ in * 4\ in

Volume = 24\ in^3

7 0
3 years ago
5n+4=39 find the value of n that makes this equation true
Bond [772]
5n + 4 = 39
5n = 39 -4
5n = 35
n = 35:5
n = 7
4 0
3 years ago
Read 2 more answers
A researcher compares two compounds (1 and 2) used in the manufacture of car tires that are designed to reduce braking distances
wariber [46]

Answer:

Step-by-step explanation:

Hello!

The objective of this experiment is to compare two compounds, designed to reduce braking distance, used in tire manufacturing to prove if the braking distance of SUV's equipped with tires made with compound 1 is shorter than the braking distance of SUV's equipped with tires made with compound 2.

So you have 2 independent populations, SUV's equipped with tires made using compound 1 and SUV's equipped with tires made using compound 2.

Two samples of 81 braking tests are made and the braking distance was measured each time, the study variables are determined as:

X₁: Braking distance of an SUV equipped with tires made with compound one.

Its sample mean is X[bar]₁= 69 feet

And the Standard deviation S₁= 10.4 feet

X₂: Braking distance of an SUV equipped with tires made with compound two.

Its sample mean is X[bar]₂= 71 feet

And the Standard deviation S₂= 7.6 feet

We don't have any information on the distribution of the study variables, nor the sample data to test it, but since both sample sizes are large enough n₁ and n₂ ≥ 30 we can apply the central limit theorem and approximate the distribution of both variables sample means to normal.

The researcher's hypothesis, as mentioned before, is that the braking distance using compound one is less than the distance obtained using compound 2, symbolically: μ₁ < μ₂

The statistical hypotheses are:

H₀: μ₁ ≥ μ₂

H₁: μ₁ < μ₂

α: 0.05

The statistic to use to compare these two populations is a pooled Z test

Z= \frac{(X[bar]_1-X[bar]_2)-(Mu_1-Mu_2)}{\sqrt{\frac{S^2_1}{n_1} +\frac{S^2_2}{n_2} } }

Z ≈ N(0;1)

Z_{H_0}= \frac{69-71-0}{\sqrt{\frac{108.16}{81} +\frac{57.76}{81} } }= -1.397

The rejection region if this hypothesis test is one-tailed to the right, so you'll reject the null hypothesis to small values of the statistic. The critical value for this test is:

Z_{\alpha  } = Z_{0.05}= -1.648

Decision rule:

If Z_{H_0} > -1.648 , then you do not reject the null hypothesis.

If Z_{H_0} ≤ -1.648 , then you reject the null hypothesis.

Since the statistic value is greater than the critical value, the decision is to not reject the null hypothesis.

At a 5% significance level, you can conclude that the average braking distance of SUV's equipped with tires manufactured used compound 1 is greater than the average braking distance of SUV's equipped with tires manufactured used compound 2.

I hope you have a SUPER day!

4 0
4 years ago
V= pi r^2h solve for h
Ivenika [448]

Divide each term by πr2 π r 2 and simplify. Divide each term in πr2h=V π r 2 h = V by πr2 π r 2 .

7 0
3 years ago
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