Using pythagorean's theorem
a^2+b^2=c^2
a being 3
b being 4
we'll get
9+16=25
where 5 is the hypotenuse and also c.
c^2 = 5^2
Answer:
Step-by-step explanation:
simplify (5-3)
PEMDAS= parentheses- e -MULTIPLY- DIVIDE - ADD- SUBTRACT
2(5-3)2+62
(2*2)2+62
8+62
70
-133/2=-66.5
If we take the upper and lower round of that number we will get the 2 consecutive numbers that make -133.
Therefore the answer is -66 & -67.
Answer:
First, we need to set up a (y−k)^2=4p(x−h). After plugging in all of your values, you would get (x-5)^2=-4(y-1). Now, we need to solve in terms of y by dividing each side by the factors that don't contain the variable
Step-by-step explanation:
