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bija089 [108]
3 years ago
13

Find the product.

Mathematics
1 answer:
valkas [14]3 years ago
7 0
(3n-10p)^2
=(3n-10p)(3n-10p)
=9n^2-10p-10p+100p^2
=9n^2-20p+100p^2
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Compare the values of the underlined digits. 503497 and 26475. The underlined is 7
shtirl [24]
The 7 is 10 times bigger in 26475 than the 7 in 503497. why? because the 7 in 26475 is in the 10's place and the 7 in 503497 is in the ones place.

If you need clarification on the 10 times bigger part...consider this whats 1×10? 10
. If the 7 was in the 100 place and the other 7 was in the 10 place then it would be 10×10=100 and so on
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3 years ago
HELP ASAP!! Identify the matrix transformation of ΔPQR, which has coordinates P(−5, −2),Q(−6, −3), and R(−2, −3), for reflection
podryga [215]

Answer:

Matrix transformation = \left[\begin{array}{ccc}-1&0\\0&1\end{array}\right]

Vertices of the new image: P'= (5,-2), Q'= (6,-3), R'= (2,-3)

Step-by-step explanation:

Transformation by reflection will produce a new congruent object in different coordinate. Reflection to y-axis made by multiplying the x coordinate with -1 and keep the y coordinate unchanged. The matrix transformation for reflection across y-axis should be: \left[\begin{array}{ccc}-1&0\\0&1\end{array}\right].

To find the coordinate of the vertices after transformation, you have to multiply the vertices with the matrix. The calculation of the each vertice will be:

P'= \left[\begin{array}{ccc}-1&0\\0&1\end{array}\right] \left[\begin{array}{ccc}-5\\-2\end{array}\right]= (5,-2)

Q'= \left[\begin{array}{ccc}-1&0\\0&1\end{array}\right] \left[\begin{array}{ccc}-6\\-3\end{array}\right]= (6,-3)

R'= \left[\begin{array}{ccc}-1&0\\0&1\end{array}\right] \left[\begin{array}{ccc}-2\\-3\end{array}\right]= (2,-3)

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Step-by-step explanation:

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