What is the area of the picture below?

What is the constant proportionality for the relationship on the graph

tankabanditka [31]

<h3>Answer: Choice A) 3.5</h3>

Work Shown:

The point (8,28) is the furthest to the right on the graph. We have x = 8 and y = 28 pair up here. Divide the y over the x

y/x = 28/8 = 3.5

side note: the tickmarks on the y axis go up by 4 each time

5 0

3 years ago

Read 2 more answers

The no. Of adel beads to that of claire's beads was the ratio 7 :4 .When adel gave 68 beads to claire the ratio become 25 :41 .

Novosadov [1.4K]

Answer:

37 beads

Step-by-step explanation:

Given that:

Adel : Claire = 7 : 4

Let Adel be = A; &

Let Claire be = C

A: C = 7 : 4

$\dfrac{A}{C} =\dfrac{7}{4}$

7C = 4A

$C = \dfrac{4A}{7}$ --- (1)

When Adel gave 68 beads to claire, we have:

C + 68 = 25:41

$\dfrac{A}{C+68}= \dfrac{25}{41}$

25(C + 68) = 41A

C + 68 = $\dfrac{41}{25}A$

$C = \dfrac{41}{25}A - 68$ --- (2)

Equating (1) and (2) together;

$\dfrac{4 * A}{7} = \dfrac{41 *A}{25} - 68$

$\dfrac{4 * A}{7}-\dfrac{41 *A}{25} = - 68$

$\dfrac{100A - 287 A}{175} =- 68$

$\dfrac{-187A}{175} = -68$

- 187 A = 175 × (-68)

-187 A = - 11900

A = - 11900/ -187

A ≅ 64

From; $C = \dfrac{4A}{7}$

$C = \dfrac{4*64}{7}$

C = 36.57

C ≅ 37 beads

4 0

3 years ago

A sound wave enters a new medium where sound travels faster. How does this affect the frequency and wavelength of the sound?

worty [1.4K]

The frequency stays the same and the wavelength decreases.

6 0

3 years ago

Read 2 more answers

Sum of cubes: (a b)(a2 – ab b2) = a3 b3 Difference of cubes: (a – b)(a2 ab b2) = a3 – b3 Which products result in a sum or diffe

valentina_108 [34]

By comparing all the options with the formula of sum of cubes and difference of cubes we get that $(x+4)\left(x^{2}-4 x+16\right)$ is sum of cubes

<h3>What is formula of sum of cubes and difference of cubes?</h3>

Formula of sum of cubes and difference of cubes are following

$(a+b)(a^2 -ab +b^2) = a^3+ b^3 \\\\\\(a - b)(a^2+ ab+ b^2) = a^3 - b^3$

(a)

$(x-4) \left(x^{2}+4 x-16\right)\\=(x-4) \left(x^{2}+4 x-4^2\right)\\\\$

by comparison with formula we can say that this is neither sum or nor difference of cubes.

(b)

$(x-1)\left(x^{2}-x+1\right)\\=(x-1)\left(x^{2}-x+1^2\right)$

by comparison with formula we can say that this is neither sum nor difference of cubes.

(c)

$(x+1)(x-1)=x^{2}-1^{2}\\$

we can say that this is neither sum nor difference of cube as it's difference of squares.

(d)

$(x+4)\left(x^{2}-4 x+16\right)\\\\(x+4)\left(x^{2}-4 x+4^2\right)$

by comparison with formula this is equal to

$x^{3}+4^{3}\\$

Hence this is sum of cubes

(e)

$(x+4)\left(x^{2}+4 x+16\right)\\(x+4)\left(x^{2}+4 x+4^2\right)$

by comparison with formula we can say that this is neither sum nor difference of cubes.

By comparing all the options with the formula of sum of cubes and difference of cubes we get that $(x+4)\left(x^{2}-4 x+16\right)$ is sum of cubes

To know more about cubes visit: brainly.com/question/107100

8 0

1 year ago

Solve the following quadratic equation for all values of x in simplest form.

Lynna [10]

Step-by-step explanation:

x = 2/5 or x = 0 Hope that will help

7 0

2 years ago