Answer:
Here we have the function:
S(t) = 500 - 400*t^(-1)
Then the rate of change at the value t, will be:
S'(t) = dS(t)/dt
This differentiation will be:
S'(t) = -400/t^2
Then:
a) the rate of change at t = 1 is:
S'(1) = -400/1^2 = -400
The rate of change after one year is -400
b) t = 10
S'(10) = -400/10^2 = -400/100 = -4
The rate of change after 10 years is -4, it reduced as the years passed, as expected.
The answer would be 0.06 or just .06
9514 1404 393
Answer:
Step-by-step explanation:
1) The slope is given by the formula ...
m = (y2 -y1)/(x2 -x1)
m = (4 -(-3))/(3 -0) = 7/3
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2) The y-intercept is the point where x=0:
(x, y) = (0, -3) . . . . . y = -3
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3) Then the slope-intercept equation is ...
y = mx + b . . . . . . . line with slope m and y-intercept b
y = 7/3x -3
Answer:
im confused
Step-by-step explanation:
