What is the equation of the line with a slope of -1/2 that passes through the point (6,-6)?

2 answers:

7 0

$y=mx+b \\ \\
\hbox{the slope } m=-\frac{1}{2} \\ \\
y=-\frac{1}{2}x+b \\
(x,y)=(6,-6) \\
-6=-\frac{1}{2} \times 6+b \\
-6=-3+b \ \ \ |+3 \\
b=-3
\\ \\
\boxed{y=-\frac{1}{2}x-3}$

lara [203]2 years ago

7 0

<span>The basic formula<span>:</span></span>
$y- y_{0} =m(x- x_{0} ) \\ y- (-6) =(- \frac{1}{2}) (x-6) \\ y=- \frac{1}{2}x-3$

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