Question

What is the equation of the line with a slope of -1/2 that passes through the point (6,-6)?

Answer 1

$y=mx+b \\ \\ \hbox{the slope } m=-\frac{1}{2} \\ \\ y=-\frac{1}{2}x+b \\ (x,y)=(6,-6) \\ -6=-\frac{1}{2} \times 6+b \\ -6=-3+b \ \ \ |+3 \\ b=-3 \\ \\ \boxed{y=-\frac{1}{2}x-3}$

Answer 2

The basic formula:
$y- y_{0} =m(x- x_{0} ) \\ y- (-6) =(- \frac{1}{2}) (x-6) \\ y=- \frac{1}{2}x-3$