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3 years ago

In the right triangle shown, mZA = 45° and AB = 12. B 12 45 How long is BC?

Mathematics

1 answer:

wel3 years ago

5 0

Answer:

6sqrt(2)=8.5

Step-by-step explanation:

Using pythagoras theorem

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Which is one of the transformations applied to the graph of f(x) = x2 to change it into the graph of g(x) = 9x? – 36X?

matrenka [14]

Answer: C. The graph of f(x)= x2 is shifted down 36 units

Step-by-step explanation:

6 0

3 years ago

Someone please help me with the perimeter and area of this problem

Tcecarenko [31]

Answer: Perimeter = 40

Area = 204

Step-by-step explanation:

Perimeter is the sum of all the sides:

11 + 12 + 17 = 40

The area of a triangle is 1/2 base x height

1/2( 17 x 24)

1/2( 408) = 204

5 0

2 years ago

A prticular type of tennis racket comes in a midsize versionand an oversize version. sixty percent of all customers at acertain

svetlana [45]

Answer:

a) P(x≥6)=0.633

b) P(4≤x≤8)=0.8989 (one standard deviation from the mean).

c) P(x≤7)=0.8328

Step-by-step explanation:

a) We can model this a binomial experiment. The probability of success p is the proportion of customers that prefer the oversize version (p=0.60).

The number of trials is n=10, as they select 10 randomly customers.

We have to calculate the probability that at least 6 out of 10 prefer the oversize version.

This can be calculated using the binomial expression:

$P(x\geq6)=\sum_{k=6}^{10}P(k)=P(6)+P(7)+P(8)+P(9)+P(10)\\\\\\P(x=6) = \binom{10}{6} p^{6}q^{4}=210*0.0467*0.0256=0.2508\\\\P(x=7) = \binom{10}{7} p^{7}q^{3}=120*0.028*0.064=0.215\\\\P(x=8) = \binom{10}{8} p^{8}q^{2}=45*0.0168*0.16=0.1209\\\\P(x=9) = \binom{10}{9} p^{9}q^{1}=10*0.0101*0.4=0.0403\\\\P(x=10) = \binom{10}{10} p^{10}q^{0}=1*0.006*1=0.006\\\\\\P(x\geq6)=0.2508+0.215+0.1209+0.0403+0.006=0.633$

b) We first have to calculate the standard deviation from the mean of the binomial distribution. This is expressed as:

$\sigma=\sqrt{np(1-p)}=\sqrt{10*0.6*0.4}=\sqrt{2.4}=1.55$

The mean of this distribution is:

$\mu=np=10*0.6=6$

As this is a discrete distribution, we have to use integer values for the random variable. We will approximate both values for the bound of the interval.

$LL=\mu-\sigma=6-1.55=4.45\approx4\\\\UL=\mu+\sigma=6+1.55=7.55\approx8$

The probability of having between 4 and 8 customers choosing the oversize version is:

$P(4\leq x\leq 8)=\sum_{k=4}^8P(k)=P(4)+P(5)+P(6)+P(7)+P(8)\\\\\\P(x=4) = \binom{10}{4} p^{4}q^{6}=210*0.1296*0.0041=0.1115\\\\P(x=5) = \binom{10}{5} p^{5}q^{5}=252*0.0778*0.0102=0.2007\\\\P(x=6) = \binom{10}{6} p^{6}q^{4}=210*0.0467*0.0256=0.2508\\\\P(x=7) = \binom{10}{7} p^{7}q^{3}=120*0.028*0.064=0.215\\\\P(x=8) = \binom{10}{8} p^{8}q^{2}=45*0.0168*0.16=0.1209\\\\\\P(4\leq x\leq 8)=0.1115+0.2007+0.2508+0.215+0.1209=0.8989$

c. The probability that all of the next ten customers who want this racket can get the version they want from current stock means that at most 7 customers pick the oversize version.

Then, we have to calculate P(x≤7). We will, for simplicity, calculate this probability substracting P(x>7) from 1.

$P(x\leq7)=1-\sum_{k=8}^{10}P(k)=1-(P(8)+P(9)+P(10))\\\\\\P(x=8) = \binom{10}{8} p^{8}q^{2}=45*0.0168*0.16=0.1209\\\\P(x=9) = \binom{10}{9} p^{9}q^{1}=10*0.0101*0.4=0.0403\\\\P(x=10) = \binom{10}{10} p^{10}q^{0}=1*0.006*1=0.006\\\\\\P(x\leq 7)=1-(0.1209+0.0403+0.006)=1-0.1672=0.8328$

7 0

3 years ago

I WILL MARK 10/10 IF U GET ANSWER CORRCET!!10 Fill in the blanks to make each equation true.

ANTONII [103]

Answer:

a) 2.6

b) -15

c) 9

d) $\frac{3}{10}-(-\frac{2}{3})=\frac{3}{10}+\frac{2}{3}=\frac{9}{30}+\frac{20}{30}=\frac{29}{30}$

e) 1.26

Step-by-step explanation:

3 0

3 years ago

What is h(p)=(p3+4p2-2) in distributive property

loris [4]

Let's solve for h.
h
p
=
p
3
+
4
p
2
−
2
Step 1: Divide both sides by p.
h
p
p
=
p
3
+
4
p
2
−
2
p
h
=
p
3
+
4
p
2
−
2
p
Answer:
h
=
p
3
+
4
p
2
−
2
p

5 0

3 years ago