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lina2011 [118]
3 years ago
10

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the

Mathematics
1 answer:
stiv31 [10]3 years ago
3 0

Answer:

8.67 seconds.

Step-by-step explanation:

I hope this helps!

You might be interested in
What is the slope of the line l described by the equation below? y=-2x+4
Masteriza [31]

Answer:

The slope of the line would be -2.

Step-by-step explanation:

Because the equation is a line, the slope is the same throughout the entire graph on the equation.

Lets let f(x)=y=-2x+4.

f(0) = -2(0) + 4 = 4

f(0)=4

f(1) = -2(1) + 4 = 2

f(1)=2

Use the equation to find slope.

m(slope) = \frac{2-4}{1-0} = \frac{-2}{1} = -2

<em>The slope would be -2.</em>

<em />

Or:

Use the equation y = mx + b where m=slope.

In the equation y=-2x+4, m=-2.

<em>The slope is -2.</em>

6 0
3 years ago
A student finds the slop of the line between (4, 3) and (-2, -2). She writes -2–4/-2–3. What mistake did she make?
TiliK225 [7]
Her mistake is that she did the change in x over the change in y. It should be the change in y over the change in x.  So:  -2-3/-2-4
7 0
3 years ago
Read 2 more answers
If there is a 4 digit code and using the digits 1-4, how many possibilities are there?
timurjin [86]

Answer:

64

Step-by-step explanation:

1

2

3

4

1, 2

1, 3

1, 4

2, 1

2, 3

2, 4

3, 1

3, 2

3, 4

4, 1

4, 2

4, 3

1, 2, 3

1, 2, 4

1, 3, 2

1, 3, 4

1, 4, 2

1, 4, 3

2, 1, 3

2, 1, 4

2, 3, 1

2, 3, 4

2, 4, 1

2, 4, 3

3, 1, 2

3, 1, 4

3, 2, 1

3, 2, 4

3, 4, 1

3, 4, 2

4, 1, 2

4, 1, 3

4, 2, 1

4, 2, 3

4, 3, 1

4, 3, 2

1, 2, 3, 4

1, 2, 4, 3

1, 3, 2, 4

1, 3, 4, 2

1, 4, 2, 3

1, 4, 3, 2

2, 1, 3, 4

2, 1, 4, 3

2, 3, 1, 4

2, 3, 4, 1

2, 4, 1, 3

2, 4, 3, 1

3, 1, 2, 4

3, 1, 4, 2

3, 2, 1, 4

3, 2, 4, 1

3, 4, 1, 2

3, 4, 2, 1

4, 1, 2, 3

4, 1, 3, 2

4, 2, 1, 3

4, 2, 3, 1

4, 3, 1, 2

4, 3, 2, 1

3 0
3 years ago
Read 2 more answers
Suppose twenty-two communities have an average of = 123.6 reported cases of larceny per year. assume that σ is known to be 36.8
Delvig [45]
We are given the following data:

Average = m = 123.6
Population standard deviation = σ= psd = 36.8
Sample Size = n = 22

We are to find the confidence intervals for 90%, 95% and 98% confidence level.

Since the population standard deviation is known, and sample size is not too small, we can use standard normal distribution to find the confidence intervals.

Part 1) 90% Confidence Interval
z value for 90% confidence interval = 1.645

Lower end of confidence interval = m-z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Lower end of confidence interval=123.6-1.645* \frac{36.8}{ \sqrt{22}}=110.69

Upper end of confidence interval = m+z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Upper end of confidence interval=123.6+1.645* \frac{36.8}{ \sqrt{22}}=136.51

Thus the 90% confidence interval will be (110.69, 136.51)

Part 2) 95% Confidence Interval
z value for 95% confidence interval = 1.96

Lower end of confidence interval = m-z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Lower end of confidence interval=123.6-1.96* \frac{36.8}{ \sqrt{22}}=108.22

Upper end of confidence interval = m+z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Upper end of confidence interval=123.6+1.96* \frac{36.8}{ \sqrt{22}}=138.98

Thus the 95% confidence interval will be (108.22, 138.98)

Part 3) 98% Confidence Interval
z value for 98% confidence interval = 2.327

Lower end of confidence interval = m-z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Lower end of confidence interval=123.6-2.327* \frac{36.8}{ \sqrt{22}}=105.34
Upper end of confidence interval = m+z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Upper end of confidence interval=123.6+2.327* \frac{36.8}{ \sqrt{22}}=141.86

Thus the 98% confidence interval will be (105.34, 141.86)


Part 4) Comparison of Confidence Intervals
The 90% confidence interval is: (110.69, 136.51)
The 95% confidence interval is: (108.22, 138.98)
The 98% confidence interval is: (105.34, 141.86)

As the level of confidence is increasing, the width of confidence interval is also increasing. So we can conclude that increasing the confidence level increases the width of confidence intervals.
3 0
4 years ago
Todd's team starts a football game. On the first play, they gain 6 yards. On the second play, they lose 12 yards. The expression
Natasha2012 [34]

-6 yards

Step-by-step explanation:

6-12 = -6 yards

they lost a total of 6 yards

3 0
3 years ago
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