Question

5 1/6 + (7 1/3)l <60

Answer 1

Answer:

$l$

Step-by-step explanation:

Given the inequality

$5\dfrac{1}{6}+7\dfrac{1}{3}l$

First, convert mixed numbers to improper fractions:

$5\dfrac{1}{6}=\dfrac{5\cdot 6+1}{6}=\dfrac{31}{6}\\ \\7\dfrac{1}{3}=\dfrac{7\cdot 3+1}{3}=\dfrac{22}{3}$

Now the inequality looks like

$\dfrac{31}{6}+\dfrac{22}{3}l$

Multiply it by 6:

$\dfrac{31}{6}\cdot 6+\dfrac{22}{3}l\cdot 6$