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-BARSIC- [3]
3 years ago
12

Can anyone solve for x? Please.

Mathematics
1 answer:
adoni [48]3 years ago
6 0

Answer:

\frac{20}{24}  =  \frac{22}{x + 22}  \\ 24 \times 22 = 20x + 20 \times 22 \\ 20x = 4 \times 22 \\ x = 88 \div 20 = 4.4

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Find the solution set s^2=16
Sever21 [200]

Answer:

4

Step-by-step explanation:

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3 years ago
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The diagram shows two straight lines. both lines intersect at point A.
Setler [38]

Following the graph as listed we can immidiately say that (1/2,-2) & (-2,-8) must be wrong. This can be seen by the fact that the line's don't intersect in quadrants 1 & 4. It also cannot be greater than -2 or y would not =-2. Thus it must be (-1/2,-2) or (-2,1/2) and because we know they don't intersect in quadrant two, t<u>he correct answer must be (-1/2,-2)</u>. So the last answer is correct for the intersection point.

<em>TLDR: (-1/2,-2) is the correct answer. </em>

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6 0
3 years ago
There are three consecutive even integers. If twice the first integer added to the second is 268, 244 find all three integers.
Rudik [331]

Answer:

The numbers would be 89,414 , 89,416, and 89,418

Step-by-step explanation:

In order to find this, start by setting the lowest number as x. Then we can determine that the next two even integers are x + 2 and x + 4. From this we can write the following equation.

2(x) + x + 2 = 268,244

3x + 2 = 268,244

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6 0
3 years ago
There are 9 students in a class: 7 boys and 2 girls.
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Answer: 9/7

Step-by-step explanation:

6 0
3 years ago
In △ABC, m∠A=39°, a=11, and b=13. Find c to the nearest tenth.
Talja [164]

For this problem, we are going to use the <em>law of sines</em>, which states:

\dfrac{\sin{A}}{a} = \dfrac{\sin{B}}{b} = \dfrac{\sin{C}}{c}


In this case, we have an angle and two sides, and we are trying to look for the third side. First, we have to find the angle which corresponds with the second side, B. Then, we can find the third side. Using the law of sines, we can find:

\dfrac{\sin{39^{\circ}}}{11} = \dfrac{\sin{B}}{13}


We can use this to solve for B:

13 \cdot \dfrac{\sin{39^{\circ}}}{11} = \sin{B}

B = \sin^{-1}{\Big(13 \cdot \dfrac{\sin{39^{\circ}}}{11}\Big)} \approx 48.1


Now, we can find C:

C = 180^{\circ} - 48.1^{\circ} - 39^{\circ} = 92.9^{\circ}


Using this, we can find c:

\dfrac{\sin{39^{\circ}}}{11} = \dfrac{\sin{92.9^{\circ}}}{c}

c = \dfrac{11\sin{92.9^{\circ}}}{\sin{39^{\circ}}} \approx \boxed{17.5}


c is approximately 17.5.

8 0
3 years ago
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