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3 years ago

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Phillips height is 190 cm Kim’s height is 95% as much as Phillips Ethan‘s height is 90% as much is Kim’s and Amy’s height is 85%

as much as Ethan’s what is the average height of them

1 answer:

inysia [295]3 years ago

3 0

Answer:

The answer is 100

Step-by-step explanation:

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Franchise Business Review stated over 50% of all food franchises earn a profit of less than $50,000 a year. In a sample of 130 c

nydimaria [60]

Answer:

We need a sample size of 564.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$\pi = \frac{81}{130} = 0.6231$

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

Based upon a 95% confidence interval with a desired margin of error of .04, determine a sample size for restaurants that earn less than $50,000 last year.

We need a sample size of n

n is found when $M = 0.04$

So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 1.96\sqrt{\frac{0.6231*0.3769}{n}}$

$0.04\sqrt{n} = 1.96\sqrt{0.6231*0.3769}$

$\sqrt{n} = \frac{1.96\sqrt{0.6231*0.3769}}{0.04}$

$(\sqrt{n})^{2} = (\frac{1.96\sqrt{0.6231*0.3769}}{0.04})^{2}$

$n = 563.8$

Rounding up

We need a sample size of 564.

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The time it takes you to go a certain distance varies inversely with the speed of travel. Suppose it takes you 4 hours to get to

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$\bf \qquad \qquad \textit{inverse proportional variation}
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\begin{array}{llll}
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\end{array}\\\\
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r=\stackrel{mph}{50}
\end{cases}\implies 4=\cfrac{k}{50}\implies 200=k
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boyakko [2]

2 (1/4)= 2.25*100= 225%
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