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2 years ago

Which of the following inequalities matches the graph? (1 point)

Mathematics

1 answer:

Lilit [14]2 years ago

8 0

Y is less than or equal to 0

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Find the commission 690.48

skad [1K]

Answer:

more information would love to help

Step-by-step explanation:

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2 years ago

Which statement is true of the function f(x) = ? Select three options.

Marianna [84]

Answer:

The function has a domain of all real numbers.

The function has a range of {y|–∞ < y <∞ }.

The function is a reflection of y=∛x

Step-by-step explanation:

Given:

f(x)=-∛x

domain is set of all values that x can take for which the function is defined, so

for above function domain= set of all real numbers

range is set of values that corresponds to the set of values of domain, so for given f(x) range={y|–∞ < y <∞ } set of real numbers

Now f(x)=-∛x hence its reflection will be

-f(x)=-(-∛x)

y=∛x !

3 0

3 years ago

Read 2 more answers

How do you divide 6114 by 63

viva [34]

You put it in a calculator and you get 97.06349206.

8 0

2 years ago

Which expression is equivalent to (5^4)^2<br> A. 25^8<br> B. 20^2<br> C. 5^8<br> D. 5^6

Yuliya22 [10]

Answer:

C. 5^8

to raise a power to another power, multiply the exponents

then multiply thr numbers

then u get 5^8

6 0

3 years ago

During the period from 1790 to 1930, the US population P(t) (t in years) grew from 3.9 million to 123.2 million. Throughout this

alex41 [277]

Answer:

Step-by-step explanation:

Given that during the period from 1790 to 1930, the US population P(t) (t in years) grew from 3.9 million to 123.2 million. Throughout this period, P(t) remained close to the solution of the initial value problem.

$\frac{dP}{dt} =0.03135P =0.0001489P^2, P(0) = 3.9$

a) 1930 population is the population at time t = 40 years taking base year as 40

We can solve the differential equation using separation of variables

$\frac{dP}{0.03135P – 0.0001489P^2 } =dt\\\frac{dP}{-P(0.03135 – 0.0001489P } =dt$

Resolve into partial fractions

$\frac{31.8979}{P} -\frac{0.00474}{0.0001489P-0.03135}$

Integrate to get

ln P -0.00474/0.0001489 (ln (0.0001489P-0.03135) = t+C

ln P -31.833 (ln (0.0001489P-0.03135) =t+C

$\frac{P}{( ( (0.0001489P-0.03135)^{31.833} } =Ae^t$

Limiting population would be infinity.

6 0

3 years ago