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VLD [36.1K]
3 years ago
9

What is the missing side length of the right triangle ? 8in and 15in

Mathematics
1 answer:
arsen [322]3 years ago
6 0

Answer:

67

Step-by-step explanation:

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What is the difference of the fractions? Use the number line to help find the answer.
vova2212 [387]
<h2>Explanation:</h2>

Hello, remember you need to write complete questions in order to get good and exact answers. Here you haven't provided any fractions, so I'll give you my own fractions.

The first fraction is:

\frac{1}{2}

The second fraction is:

\frac{1}{4}

So let's say that difference is:

\frac{1}{2}-\frac{1}{4}

Therefore, the result is:

\frac{1}{2}-\frac{1}{4}=\frac{1}{4}

The representation of this problem is shown using the number line below. As you can see, we have written both 1/2 and 1/4 and the difference is also indicated giving the result 1/4. That is, if we walk from 1/4 to 1/2 we'll walk 1/4 units.

6 0
3 years ago
Read 2 more answers
BD Bisects ABC. Find the value of x in the image shown below
IRISSAK [1]

Answer:

Since BD Bisects ABC,

Hence,

Angle CBD=Angle DBA

-> 55°=x°+12°

-> x° =55°-12°

-> x° =43°

6 0
3 years ago
If 2x-10=4, what must x squelch to?
mr_godi [17]

Answer:

x=7

Step-by-step explanation:

2x-10=4 add 10 to both sides

2x=14 divide both sides by 2

x=7

3 0
3 years ago
A machine that produces ball bearings has initially been set so that the true average diameter of the bearings it produces is .5
lara [203]

Answer:

7.3% of the bearings produced will not be acceptable

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 0.499, \sigma = 0.002

Target value of .500 in. A bearing is acceptable if its diameter is within .004 in. of this target value.

So bearing larger than 0.504 in or smaller than 0.496 in are not acceptable.

Larger than 0.504

1 subtracted by the pvalue of Z when X = 0.504.

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.504 - 0.494}{0.002}

Z = 2.5

Z = 2.5 has a pvalue of 0.9938

1 - 0.9938= 0.0062

Smaller than 0.496

pvalue of Z when X = -1.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.496 - 0.494}{0.002}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

0.0668 + 0.0062 = 0.073

7.3% of the bearings produced will not be acceptable

4 0
3 years ago
Who can help me with this for algebra 2
Anuta_ua [19.1K]
The answer to this equation is

x= 1, -3
7 0
2 years ago
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