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Stella [2.4K]
3 years ago
7

the length of a rectangle is 11 feet more than its width. The area of the rectangle is 276 square feet.What are the dimensions o

f the rectangle?

Mathematics
1 answer:
kozerog [31]3 years ago
8 0
Here it is. I marked A as area, and a is length and b width.

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Find the product in simplest form. State any restrictions on the variable.
inn [45]

Answer:

−x4−3x3−21x2−49x−6

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x2

Step-by-step explanation:

if you have more problems search up algebra calculator

4 0
3 years ago
Evaluate the following expression:
Molodets [167]

Answer:

Astronomers were trying to find the weight of six planets - Mars, Venus, Pluto, Jupiter, Mercury, and Saturn. The number of planets lighter than Mars was equal to the number of planets heavier than Venus. Saturn was heavier than Mars and Mercury were heavier than Pluto. Venus was lighter than Mars. Saturn was not the heaviest planet.

Step-by-step explanation:

7 0
3 years ago
Which of these relations on the set {0, 1, 2, 3} are equivalence relations? If not, please give reasons why. (In other words, if
Delicious77 [7]

Answer:

(1)Equivalence Relation

(2)Not Transitive, (0,3) is missing

(3)Equivalence Relation

(4)Not symmetric and Not Transitive, (2,1) is not in the set

Step-by-step explanation:

A set is said to be an equivalence relation if it satisfies the following conditions:

  • Reflexivity: If \forall x \in A, x \rightarrow x
  • Symmetry: \forall x,y \in A, $if x \rightarrow y,$ then y \rightarrow x
  • Transitivity: \forall x,y,z \in A, $if x \rightarrow y,$ and y \rightarrow z, $ then x \rightarrow z

(1) {(0,0), (1,1), (2,2), (3,3)}

(3) {(0,0), (1,1), (1,2), (2,1), (2,2), (3,3)}

The relations in 1 and 3 are Reflexive, Symmetric and Transitive. Therefore (1) and (3) are equivalence relation.

(2) {(0,0), (0,2), (2,0), (2,2), (2,3), (3,2), (3,3)}

In (2), (0,2) and (2,3) are in the set but (0,3) is not in the set.

Therefore, It is not transitive.

As a result, the set (2) is not an equivalence relation.

(4) {(0,0), (0,1), (0,2), (1,0), (1,1), (1,2), (2,0), (2,2), (3,3)}

(1,2) is in the set but (2,1) is not in the set, therefore it is not symmetric

Also, (2,0) and (0,1) is in the set, but (2,1) is not, rendering the condition for transitivity invalid.

5 0
3 years ago
It costs $6.45 to buy 5 songs on I-tunes. How much does it cost to buy 20 songs?
babunello [35]

Answer:$25.80

Step-by-step explanation:

6.45/5 = 1.29

1.29 x 20 =25.80

5 0
2 years ago
Find the zeroes of the polynomial function f(x)=x^4-5x^3+11x^2-25x+30.
katen-ka-za [31]

Step-by-step explanation:

x⁴ − 5x³ + 11x² − 25x + 30

x⁴ − 5x³ + 6x² + 5x² − 25x + 30

x² (x² − 5x + 6) + 5 (x² − 5x + 6)

(x² + 5) (x² − 5x + 6)

(x² + 5) (x − 2) (x −3)

The zeros are 2, 3, and ±√5i.

7 0
4 years ago
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