Let x---------> length original square side x1--------> length resulting rectangle y1--------> wide resulting rectangle A1--------> area resulting rectangle
we know that x1=x+2 y1=x-2 A1=60 in² 60=(x+2)*(x-2)--------> 60=x²-2x+2x-4-------> 60=x²-4------> x²=64 x1=8 x2=-8
the solution is x=8 in <span>the area of the original square is 8*8-------> 64 in</span>²
