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Anarel [89]
3 years ago
15

• A car uses 30 gallons of gasoline for a trip of 800 miles. How many gallons would

Mathematics
1 answer:
nevsk [136]3 years ago
7 0

Quantity of gasoline needed by a car to run 800 miles = 30 gallons

Quantity of gasoline needed by a car to run 1 mile =

= 30 ÷ 800

= 0.0375 gallons

So , to run 1 mile a car would need = 0.0375 gallons of oil

To run 700 miles the quantity of gasoline needed =

= 700 × 0.0375

= 26.25 gallons of gasoline

Therefore , a car will use 26.25 gallons of gasoline on a trip of 700 miles .

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alexgriva [62]

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6 0
2 years ago
Read 2 more answers
Determine whether the relation represents a function.
-Dominant- [34]

Answer:

it does not because it would not pass the straight line test

Step-by-step explanation:

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6 0
2 years ago
Jake has a pocket full of dimes and quarters. The total value of his change is $2.05. Let D D represent the number of dimes, and
m_a_m_a [10]
Let A be the number of Dimes & B the number of Quarters, the linear equation is as follows:
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4 0
3 years ago
Which of the following functions is graphed below? Please i need help!!!
artcher [175]

Answer: A

Step-by-step explanation:

If you look only at the ranges provided for x A is the only one that fits the graph. The domain of the first function (x^3-3) is everything equal to or less than 2. The equal to is represented by the closed circle at point (2,5) which represents that this value is included for that function. The other function continues on with values greater than 2, but does not include the x value 2 as it has an open circle at point (2,10).

8 0
3 years ago
Solve by elimination<br> -3x+2y=10<br> -2x-y=-5
Nataly [62]
First you need to get two similar terms to eliminate, I'll do y:
-3x + 2y = 10
-4x - 2y= -10
And then you minus
x = 20
Now you can substitute x in to one of the equations to find y:
-60 + 2y = 10
+ 60
2y = 70
÷ 2
y = 35
So your values are y = 35 and x = 20. Hope this helps!
6 0
3 years ago
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