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3 years ago

• A car uses 30 gallons of gasoline for a trip of 800 miles. How many gallons would

Mathematics

1 answer:

nevsk [136]3 years ago

7 0

Quantity of gasoline needed by a car to run 800 miles = 30 gallons

Quantity of gasoline needed by a car to run 1 mile =

= 30 ÷ 800

= 0.0375 gallons

So , to run 1 mile a car would need = 0.0375 gallons of oil

To run 700 miles the quantity of gasoline needed =

= 700 × 0.0375

= 26.25 gallons of gasoline

Therefore , a car will use 26.25 gallons of gasoline on a trip of 700 miles .

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Evaluate the expression. (1.5)2(1.5) −2⋅(1.5)4

aleksklad [387]

Is this (1.5)2(1.5) / -2(1.5)4? or is it (1.5)2(1.5) - 2(1.5)4?

First option:
4.5/-12 = -0.375

Second option
4.5-12 = -7.5

8 0

3 years ago

Write the equation of a line that is perpendicular to y = -8 3 x + 4 and goes through the point (5, 2)

zhuklara [117]

Answer:

y = 3/8x + 1/8

Step-by-step explanation:

The slope of a perpendicular line is the opposite and reciprocal of the original slope.

-8/3 -> 3/8

Find the new y-intercept.

y = 3/8x + b

2 = 3/8(5) + b

2 = 1.875 + b

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Best of Luck!

5 0

3 years ago

Tanya [424]

Answer:

The gold vein is 96 miles away from the farthest gold dust strike.

Step-by-step explanation:

Distance Between two Points in the Plane

Given two points A(x,y) and B(w,z), the distance between them is:

$d=\sqrt{(z-y)^2+(w-x)^2}$

The prospector positioned the gold vein at (-2,9) and the farthest gold dust strike at (94,9). We are required to calculate the distance between these two points. Use the formula:

$d=\sqrt{(9-9)^2+(94-(-2))^2}$

$d=\sqrt{0^2+96^2}$

$d=\sqrt{96^2}=96$

The distance is 96 units, but we know each unit on the graph represents 1 mile, thus the gold vein is 96 miles away from the farthest gold dust strike.

8 0

2 years ago

Solve the system of equations.

Tom [10]

Easiest method you can apply (Cramer's one). "Thanks me" if i've been helpful