Let q be the number of 25 cent coins.
Let d be the number of 10 cent coins.
0.25q+0.10d= 3.95...(1)
q-d=6...(2)
(2)-> q-d= 6
q-d+d= 6+d
q= 6+d...(2a)
(2a)-> (1) 0.25q+0.10d=3.95
0.25(6+d)=0.10d= 3.95
1.95+0.25d+0.10d= 3.95
0.35d= 3.95-1.5
0.35d/0.35= 2.45/0.35
d= 7...(3)
(3)->(2) q-d= 6
q-7= 6
q=6+7
q= 13
There are 13 quarters and 7 dimes.
Answer:
24
Step-by-step explanation:
Answer:
3x^2+6x-2
Step-by-step explanation:
(5x2 + 4x + 3) - (2x2 - 2x + 5)
5x^2+4x+3-2x^2+2x-5
3x^2+6x-2
Answer:
The steps are to first find the samllest multiple for the denominator and then cross multiply the numerator with the other denominator nd these you go.
Example : number one is 3/20. LEARN
Step-by-step explanation:
Okay fractions are EEEZZZ