Answer:
#Set of three most popular names in 2007
male_names = {'Oliver', 'Declan', 'Henry'}
#The male_names set is displayed to the user
print(male_names)
#The name to be removed is accepted from the user as a string
remove_name = str(input("Enter name to remove: "))
#The name to be added is accepted from the user as a string
add_name = str(input("Enter name to add: "))
#The remove method of a set is use to remove the received remove_name
male_names.remove(remove_name)
#The add method of a set is use to add the received add_name
male_names.add(add_name)
#The new set of male_names is displayed to the user
print(male_names)
Explanation:
They can hold a lot of information is what you're looking for , i can remember having this question back when i did my GCSEs <span />
Answer: the employment demand would increase.
Explanation:
Several factors affect the employment demand especially in a field as peculiar as engineering, the cumulative build up of unemployed graduates and the skill set required to fit into the present working structure is also of Paramount importance. The evaluation method for recruitment seeks to function based on this rationale by selecting a few amongst many.
Answer:
a) 500 Kbps b) 64 sec c) 320 sec
Explanation:
a) We define the throughput of a network, as the actual maximum transmission rate that the network is able to deliver, which in this case is equal to the lowest transmission rate of any of the links that the traffic must go through:
R1 =500 kbps
b) If the file size is given in bytes, and we have the throughput in bps, we need to convert to bits first, as follows:
4*10⁶ bytes * (8 bits/byte) = 32*10⁶ bits.
The time needed to transfer the file, will be given by the quotient between the file size and the throughput, as follows:
t = 32*10⁶ bits / 500*10³ bits/sec = 64 sec
c) If the transmission rate R2 is reduced to 100 kbps, R2 becomes the lowest transmission rate in the network, so it becomes the new throughput.
So, the time needed for the same file to be transferred to host B is as follows:
t= 32*10⁶ bits / 100*10³ bits/sec = 320 sec
