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bagirrra123 [75]
1 year ago
5

If you want to stop a loop before it goes through all of its iterations, the break statement may be used. Group of answer choice

s True False
Computers and Technology
1 answer:
NeX [460]1 year ago
6 0

Answer:

Answer is true

Explanation:

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When Adobe Photoshop was released for the first time? A: 1984 B: 1990 C: 1991 D: 1992
Natalija [7]

Answer:

B

Explanation:

4 0
3 years ago
The percentage of typical calls that would reach a respondent eligible to participate in a project is called the
Anna35 [415]

The percentage of the calls that would reach a respondent eligible to participate in a project is called the Response rate (survey) .

<h3>What is Response rate (survey)?</h3>

In survey research, the response rate is called the return rate as it is said to be the number of people who are said to have answered the survey divided by the total number of population.

Note that The percentage of the calls that would reach a respondent eligible to participate in a project is called the Response rate (survey) .

Learn more about project from

brainly.com/question/25009327

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3 0
2 years ago
If your computer is frozen what is something you would do to troubleshoot the problem ​
SpyIntel [72]

Answer:

Ctrl+Alt+Del

Explanation:

It will take you to the task manager and you can highlight the program that is frozen, right click on it and select end task. Or hard reboot as a last resort.

4 0
1 year ago
Write a program that prompts the user to enter the number of integer numbers you need to enter, then ask user to enter these int
nadya68 [22]

Answer:

import java.util.Scanner;

public class Main

{

public static void main(String[] args) {

 Scanner ob = new Scanner(System.in);

 System.out.println("How many numbers? ");

 int n = ob.nextInt();

       int[] arr = new int[n];  

 for (int i=0; i<n; i++) {

     System.out.print("Enter the number: ");

     arr[i] = ob.nextInt();

 }

    System.out.println(indexOfLargestElement(arr));

}

public static int indexOfLargestElement(int[] arr) {

    int max = arr[0];

    int maxIndex = 0;

    for (int i=0; i<arr.length; i++) {

        if (arr[i] >= max) {

            max = arr[i];

            maxIndex = i;

        }

    }

    return maxIndex;

}

}

Explanation:

Create a method called indexOfLargestElement that takes one parameter, an array

Initialize the max and maxIndex

Create a for loop iterates throgh the array

Check each element and find the maximum and its index

Return the index

Inside the main:

Ask the user to enter how many numbers they want to put in array

Get the numbers using a for loop and put them inside the array

Call the indexOfLargestElement method to find the index of the largest element in the array

8 0
3 years ago
Where can I learn how you hack?​
morpeh [17]

Answer:

www.udemy.com

5 0
2 years ago
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