Complete question is;
A model for a company's revenue from selling a software package is R = -2.5p² + 500p, where p is the price in dollars of the software. What price will maximize revenue? Find the maximum revenue.
Answer:
Price to maximize revenue = $100
Maximum revenue = $25000
Step-by-step explanation:
We are told that:
R = -2.5p² + 500p, where p is the price in dollars of the software.
The maximum revenue will occur at the vertex of the parabola.
Thus, the price at this vertex is;
p = -b/2a
Where a = - 2.5 and b = 500
Thus:
p = -500/(2 × -2.5)
p = -500/-5
p = 100 in dollars
Maximum revenue at this price is;
R(100) = -2.5(100)² + 500(100)
R(100) = -25000 + 50000
R(100) = $25000
Answer:
It'd be 4/15
Step-by-step explanation:
The total marbles is 6, so for black it's 4/6, but it's not being put back in so for the next one, the denominator would be 5. For green it's 2/5
4/6 times 2/5 equal 4/15
Hope this helps!
Answer:
-12x
Step-by-step explanation:
solution:
4x(-3)
-4x×3
-12x
Answer:
A
Step-by-step explanation:
9x4=36
36+7=43
Step-by-step explanation:
1) Thousands
2) 100 thousands
3) tens
