The hull speed of the Santa Monica in terms of the length, ln of the Nina Pinta is given as a√b where a = 1.34 and b = ln - 10
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more numbers and variables.
Given that:
v = 1.34√l
where l is the hull length in feet and v is the hull speed in knots.
Santa Monica has a hull length that is 10 ft shorter than that of the Nina Pinta and ln is the length of Nina. Hence:
v = 1.34√(ln - 10) = a√b
The hull speed of the Santa Monica in terms of the length, ln of the Nina Pinta is given as a√b where a = 1.34 and b = ln - 10
Find out more on equation at: brainly.com/question/2972832
#SPJ1
Answer:
$246
Step-by-step explanation:
6 x 9 + 12 x 16= 246
So the first thing you have to do is look at the input and output values and find the pattern. This is probably the hardest part. So 32-12=20 and 14-12=2 so we found the pattern all you have to do is find whats missing. So we have a blank and then a 14, all you do is add 12 to the 14 to find the input so the input for that would be 26 and now to find the other missing term you subtract 12 and that gives you -22. I hoped that helped.
Answer:
Step-by-step explanation:
The function of a continuous random variable, whose integral over an interval provides the likelihood that the value of the variable is just inside the same interval while The cumulative distribution function (FX) provides the possibility that the random variable X is not up to or equal to a particular amount x. the formula for calculating it is: Summing the values for every one of the outcomes less than or equal to x will give the solution.
The step by step explanation to this question are in the athached images below
Answer:
40.1
Step-by-step explanation:
Because the order of operations (Bodmas or Pedmas) tells you to add from left to right. So you would do 18.79 + 2.11 = 20.9, then you would do 20.90 + 1.92 (Add 0 at the end of 20.9) = 22.81. Then you will add 22.81 + 17.28 = 40.1. So your answer is 40.1. Hope this helps!
