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Vsevolod [243]
3 years ago
14

Solve for x. x = [?] 5x - 7/. 3x + 27

Mathematics
2 answers:
Tanzania [10]3 years ago
8 0

Step-by-step explanation:

5x-7+3x+27=180

8x+20=180

8x=160

x=20°.

hope this helps you.

enot [183]3 years ago
6 0

Answer:

5x - 7 + 3x + 27 = 180 \\  5x  + 3x + 27 - 7  = 180 \\ 8x + 20 = 180 \\ 8x = 180 - 20 \\ 8x = 160 \\ d \: b \: s \: by \: 8 \\  8x \div 8 = 160 \div 8 \\ x = 20

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Find MP………………………………….
devlian [24]

Answer:

MP = 29

Step-by-step explanation:

MP = 17 + 3y

5y + 9 = 17 + 3y

      -9    -9

5y = 8 + 3y

-3y        -3y

2y = 8

2y / 2 = 8 / 2

y = 4

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MP = 29

5 0
1 year ago
For a certain​ candy, 15​% of the pieces are​ yellow, 1010​% are​ red, 2020​% are​ blue, 55​% are​ green, and the rest are brown
MatroZZZ [7]
A) the probability it is brown would be 50%; the probability it is yellow or blue would be 35%; the probability it is not green is 95%; the probability it is striped is 0%.
B) the probability of all brown would be 12.5%; the probability that the third one is the first red one drawn is 8.1%; the probability that none are yellow is 61.4%; the probability that at least one is green is 14.3%.

Explanation:
A) The probability that it is brown is the percentage of brown we have.  Brown is not listed, so we subtract what we are given from 100%:
100-(15+10+20+5) = 100-(50) = 50%.  The probability that one drawn is yellow or blue would be the two percentages added together:  15+20 = 35%.  The probability that it is not green would be the percentage of green subtracted from 100:  100-5=95%.  Since there are no striped candies listed, the probability is 0%.
B) Since we have an infinite supply of candy, we will treat these as independent events.  All 3 being brown is found by taking the probability that one is brown and multiplying it 3 times:
0.5*0.5*0.5 = 0.125 = 12.5%.  
To find the probability that the first one that is red is the third one drawn, we take the probability that it is NOT red, 100-10 = 90% = 0.9, for the first two, and the probability that it IS red, 10% = 0.1, for the last:
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The probability that none are yellow is found by raising the probability that the first one is not yellow, 100-15=85%=0.85, to the third power:

0.85^3 = 0.614 = 61.4%.

The probability that at least one is green is computed by subtracting 1-(probability of no green).  We first find the probability that all three are NOT green:
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1-0.857375 = 0.143 = 14.3%.
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SpyIntel [72]
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ELEN [110]

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