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solong [7]
3 years ago
10

What is mitosis in a living cell?

Chemistry
1 answer:
Stells [14]3 years ago
3 0
A-sexual reproduction of the cell
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Calculate the percent ionization of formic acid (hco2h) in a solution that is 0.311 m in formic acid and 0.189 m in sodium forma
ohaa [14]
<span>Answer: 0.094%


</span><span>Explanation:
</span>
<span></span><span /><span>
1) Equilibrium chemical equation:
</span><span />

<span>Only the ionization of the formic acid is the important part.
</span><span />

<span>HCOOH(aq) ⇄ HCOO⁻(aq) + H⁺(aq).
</span><span />

<span>2) Mass balance:
</span><span />

<span>                   HCOOH(aq)     HCOO⁻(aq)     H⁺(aq).

Start             0.311                 0.189

Reaction       - x                      +x                   +x

Final             0.311 - x          0.189 + x            x


3) Acid constant equation:
</span><span />

<span>Ka = [HCOO-] [N+] / [HCOOH] = (0.189 + x) x / (0.311 -x)
</span><span />

<span>= (0.189 + x )x / (0.311 - x) = 0.000177


4) Solve the equation:


You can solve it exactly (it will lead to a quadratic equation so you can use the quadratiic formula). I suggest to use the fact that x is much much smaller than 0.189 and 0.311.
</span><span />

<span>With that approximation the equation to solve becomes:


</span><span>0.1890x / 0.311 = 0.000177, which leads to:</span>
<span /><span>
x = 0.000177 x 0.311 / 0.189 = 2.91 x 10⁻⁴ M


5) With that number, the percent of ionization (alfa) is:
</span><span />

<span>percent of ionization = (moles ionized / initial moles) x 100 =
</span><span>
</span><span>
</span><span>percent ionization = (concentration of ions / initial concentration) x 100 =
</span><span>
</span><span>
</span><span>percent ionization = (0.000291 / 0.311)x 100 = 0.0936% = 0.094%
</span>
<span></span><span />
8 0
3 years ago
Wafting the air above a chemical is one way to it directly
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To smell it directly
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4 years ago
Henri Becquerel and the Curies are famous for discovering that the atom is not indivisible, a belief held since the time of the
Rainbow [258]
Henri Becquerel discovered radioactivity and it was the Curies who made experiments about the concept and became known for their d
3 0
3 years ago
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How many moles of gas would you have if you have a volume of 38.0 L under a pressure of 1430 mmHg at standard temperature
seraphim [82]

Answer: There are 3.2 moles of gas if you have a volume of 38.0 L under a pressure of 1430 mmHg at standard temperature.

Explanation:

Given: Volume = 38.0 L

Pressure = 1430 mm Hg (1 mm Hg = 0.00131579 atm) = 1.9 atm

Temperature = 273.15 K

Using ideal gas equation, the moles of gas will be calculated as follows.

PV = nRT\\

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T =temperature

Substitute the values into above formula as follows.

PV = nRT\\1.9 atm \times 38.0 L = n \times 0.0821 L atm/mol K \times 273.15 K\\n = \frac{1.9 atm \times 38.0 L}{0.0821 L atm/mol K \times 273.15 K}\\= 3.2 mol

Thus, we can conclude that there are 3.2 moles of gas if you have a volume of 38.0 L under a pressure of 1430 mmHg at standard temperature.

5 0
3 years ago
If D+2 would react with E-1, what do you predict the formula to be. A) DE B)D2E C)DE2 D) D2E2
allochka39001 [22]
All you need to do the cross the charges and put it as suffixes. 

D+2 + E-1 ----> DE2

answer is C
5 0
3 years ago
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