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2 years ago

Ozone has a molecular formula of O3. If 7.92*1024 atoms of oxygen react to form ozone, how many

Chemistry

1 answer:

prisoha [69]2 years ago

7 0

337.92 moles of Ozone will be produced

1 Oxygen atom is 8 g

1 mole of ozone, O3 = 8 * 3 = 24 g

7.92 * 1024 = 8110.08 g

1 mole = 24 g

? moles = 8110.08 g

? = 337.92 moles

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____ N2 + ___ H2 --> ____ NH3 Reaction :

Fiesta28 [93]

N2 +H2 →2 NH3

"Reactants Products Nitrogen 2 2 Hydrogen 2 6 Since NH3 is multiplied by a coefficient of 2 there are now 2 nitrogens and 6 hydrogens. The 6 hydrogens come from the 2 multiplied by the subscript of 3."

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3 years ago

A 12.0-liter sample of air at 25°C and 1.00 atm pressure was collected and dried. After drying, the volume of the sample was exa

zmey [24]

Answer: The mass percent of water in the original air sample is 4.16 %

Explanation:

We are given:

Volume of moist air = 12.0 L

Volume of dry air = 11.50 L

Volume of water lost = (12.0 - 11.50) L = 0.50 L

Here, the percent by mass ratio will be equal to the percent by volume ratio as the number of moles is directly related to the volume.

To calculate the volume percentage of water in the air, we use the equation:

$\text{Volume percent of water}=\frac{\text{Volume of water}}{\text{Volume of air}}\times 100$

Putting values in above equation, we get:

$\text{Volume percent of water}=\frac{0.50L}{12.00L}\times 100\\\\\text{Volume percent of water}=4.16\%$

Hence, the mass percent of water in the original air sample is 4.16 %

8 0

3 years ago

When an ionic bond forms what type of ions are joined?

denis-greek [22]

It usually becomes a positive ion, or cation.

6 0

3 years ago

Select all of the below statements that accurately describe the proper Lewis structure for CBr2F2.- The formal charge on each br

Yuri [45]

Answer:

There are 12 lone pairs of electrons on the molecule.

The formal charge on carbon is zero.

There are 4 covalent bonds within the molecule.

Explanation:

The formal charge(FC) can be calculated by the equation:

FC = V - N - B/2, where V is the number of the valence electrons of the neutral element, N is the number of non-bonding valence electrons, and B is the total of electrons shared in bond.

The Lewis structure is represented in the image below. F and Br have 7 valence electrons and C 4 valence electrons.

So, for C, FC = 4 - 0 - 8/2 = 0

For the both Br, FC = 7 - 6 - 2/1 = 0

For the both F, FC = 7 - 6 - 2/1 = 0

For the structure, we can see that there are 12 lone pairs of electrons on the molecule (3 in each Br and 3 in each F).

All the bonds are covalent because the atoms are sharing a pair of electrons, so there are 4 covalent bonds within the molecule.

6 0

3 years ago

Mr. Whiteman has two stock solutions of sulfuric acid (H2SO4) in the supply closet: 12.1 M and 6.0 M. If he wants to make 10.0 m

ss7ja [257]

Answer:

12.1-M requires less volume of stock solution.

Explanation:

Hello there!

In this case, according to the foundations of dilution processes, it turns out convenient to remember that the moles of the solute before and after the dilution remains the same; for that reason we use the following equation:

$M_1V_1=M_2V_2$

Relating the initial and final molarities and volumes. Now, it is seen that V2 is 10.0 mL and M2 is 1.0 M, which means that if we solve for V1 for 12.1 M and 6.0 M, we obtain the following volumes:

$V_1=\frac{M_2V_2}{M_1} \\\\V_1^{12.1M}=\frac{1.0M*10.0 mL}{12.1M}=0.826mL\\\\V_1^{6.0M}=\frac{1.0M*10.0 mL}{6.0M}=1.67mL$

Therefore, since the 12.1-M solution requires less volume of stock solution, it makes sense to use this one as the initial solution.

Best regards!

5 0

2 years ago