Help me!!! I don’t really understand this

What is the zero of the following function, f(x) = –(2/7) x − 10?

Stels [109]

Answer:

Step-by-step explanation:

the zeros of a function f are found by solving the equation f(x) = 0. Example 1. Find the zero of the linear function f is given by. f(x) = -2 x + 4 I hope this helps.

7 0

4 years ago

If sample bias exists, then we can easily trust using the sample as representative of the

Lina20 [59]

<h3>Answer: False</h3>

Explanation:

If the sample is biased, then it does not represent the population. A biased sample favors one or more groups over others.

For example, if the sample consisted of only men, then the sample is biased toward men and leaves out women from the group. Hence, this sample does not represent everyone.

6 0

3 years ago

Read 2 more answers

Explain how the Quotient of Powers was used to simplify this expression. 2 to the fifth power, over 8 = 22 By finding the quotie

astraxan [27]

Answer:

we can do it by simplifying 8 to $2^3$ to make both powers base two, and subtracting the exponents.

Step-by-step explanation:

We have been given the expression $\frac{2^5}{8}=2^2$

8 can be rewritten as $2^3$

Hence, the given expression becomes

$\frac{2^5}{2^3}=2^2$

After subtracting the exponents on left hand side of the equation we get:

$2^2=2^2$

we can do it by simplifying 8 to $2^3$ to make both powers base two, and subtracting the exponents.

6 0

4 years ago

Read 2 more answers

Points A and B have coordinates (3,1,2) and (1,-5,4) respectively. Point C lies on line AB such that AC:BC=3:2. Find position ve

Sever21 [200]

Answer:

The position vector of point C is <-3 , -17 , 8> or -3i - 17j + 8k

Step-by-step explanation:

* Lets revise how to solve the problem

- If the endpoints of a segment are (x1 , y1 , z1) and (x2 , y2 , z2), and

point (x , y , z) divides the segment externally at ratio m1 :m2, then

$x=\frac{m_{1}x_{2}-m_{2}x_{1}}{m_{1} -m_{2}},y=\frac{m_{1}y_{2}-m_{2}y_{1}}{m_{1}-m_{2}},z=\frac{m_{1}z_{2}-m_{2}z_{1}}{m_{1}-m_{2}}$

* Lets solve the problem

∵ AB is a segment where A = (3 , 1 , 2) and B = (1 , - 5 , 4)

∵ Point C lies on line AB such that AC : BC=3 : 2

∵ From the ratio AC = 3/2 AB

∴ C divides AB externally

- Lets use the rule above to find the coordinates of C

- Let Point A is (x1 , y1 , z1) , point B is (x2 , y2 , z2) and point C is (x , y , z)

and AC : AB is m1 : m2

∴ x1 = 3 , x2 = 1

∴ y1 = 1 , y2 = -5

∴ z1 = 2 , z2 = 4

∴ m1 = 3 , m2 = 2

- By using the rule above

∴ $x=\frac{3(1)-2(3)}{3-2}=\frac{3-6}{1}=\frac{-3}{1}=-3$

∴ $y=\frac{3(-5)-2(1)}{3-2}=\frac{x=-15-2}{1}=\frac{-17}{1}=-17$

∴ $z=\frac{3(4)-2(2)}{3-2}=\frac{12-4}{1}=\frac{8}{1}=8$

∴ The coordinates fo point c are (-3 , -17 , 8)

* The position vector of point C is <-3 , -17 , 8> or -3i - 17j + 8k

3 0

3 years ago

Please help! Give the answer and how you got it

Ronch [10]

The distance between the points C(-3,1) and D(5,6) is 10.3 units.

<u>Step-by-step explanation:</u>

Let us consider CD is a line segment.

The point C is (-3,1) and D is (5,6).

The Cartesian formula for line is used to find the length between the CD.

Distance between two points = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ .

The points are (-3,1) and (5,6).

= $\sqrt{(6-(-3))^2+(6-1)^2}$ .

= $\sqrt{(6+3)^2+(6-1)^2}$

= $\sqrt{9^2+5^2}$ .

= $\sqrt{81+25}$ .

= $\sqrt{106}$ .

=10.295 ≈ 10.3.

Distance between two points 10.3 units.

7 0

4 years ago