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3 years ago

Answer needed ASAP !!!!

Mathematics

2 answers:

kumpel [21]3 years ago

6 0

Answer:

The answer is C)

Step-by-step explanation:

if you graph it on desmos they are the same line.

wel3 years ago

3 0

Answer:

C. they are the same line

Step-by-step explanation:

6x -2y = 16

2y = 6x - 16

y = 3x - 8

This line has slope = 3

y = 3x - 8; this line has slope = 3

When slopes are the same, y intercepts are the same. C. they are the same line

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Please help me This question is so hard even the computer can’t get it

victus00 [196]

Answer:

First box: 18

Second box: 40.5

Third box: 45

Step-by-step explanation:

9 km/m

6 0

3 years ago

Read 2 more answers

If a new data point at 12 is added to the graph , which will be true ?

Orlov [11]

Answer:

3. The mean will increase more than median, but both will increase.

Step-by-step explanation:

We have been given a dot plot. We are asked to find the true statement, if a new data point at 12 is added to our given dot plot.

Since we know that an large valued outlier affects mean more than median, so mean will increase more than median.

Let us check this using our given information. Our data set before adding 12 is:

1, 2, 2, 2, 3, 4, 4, 4, 5.

We can see that our data set has odd number (9) of data points, so median will be the value of 5th term, that is 3.

$\text{Mean}=\frac{1+2+2+2+3+4+4+4+5}{9}$

$\text{Mean}=\frac{27}{9}=3$

Therefore, mean of our data set is 3.

Upon adding a data point at 12, our new data set will be:

1, 2, 2, 2, 3, 4, 4, 4, 5, 12.

Now our data set has 10 terms, so median will be the average of 5th and 6th term.

$\text{Median}=\frac{3+4}{2}$

$\text{Median}=\frac{7}{2}=3.5$

Therefore, the median of new data set will be 3.5.

$\text{Mean}=\frac{1+2+2+2+3+4+4+4+5+12}{10}$

$\text{Mean}=\frac{39}{10}$

$\text{Mean}=3.9$

Therefore, mean of new data set will be 3.9.

Upon looking at our given statements we can see that 3rd statement is true as mean and median both increased after adding 12 to our data set, but mean increased more that median. Mean and median before adding 12 was 3; but after adding 12 median became 3.5, while mean became 3.9 (which is greater than mean).

3 0

3 years ago

Read 2 more answers

The area of an 14-cm-wide rectangle is 322 cm2. What is its length? The length is cm.

Anika [276]

Answer:

The length of rectangle is 23 cm.

Step-by-step explanation:

DIAGRAM :

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large{14\ cm}}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large{14\ cm}}\put(-0.5,-0.4){\bf}\put(-0.5,3.2){\bf}\put(5.3,-0.4){\bf}\put(5.3,3.2){\bf}\end{picture}$

$\begin{gathered}\end{gathered}$

SOLUTION :

Here's the required formula to find the length of rectangle :

${\longrightarrow{\pmb{\sf{A_{(Rectangle)} = l \times b}}}}$

A = Area
l = length
b = breadth

Substituting all the given values in the formula to find the length of rectangle :

$\begin{gathered}\qquad{\longrightarrow{\sf{A_{(Rectangle)} = l \times b}}}\\\\\qquad{\longrightarrow{\sf{322 = l \times 14}}}\\\\\qquad{\longrightarrow{\sf{322 = 14l}}}\\\\\qquad{\longrightarrow{\sf{l = \dfrac{322}{14}}}}\\\\\qquad{\longrightarrow{\sf{l = \cancel{\dfrac{322}{14}}}}}\\\\\qquad{\longrightarrow{\sf{l = 23 \: cm}}}\\\\\qquad{\star{\underline{\boxed{\sf{ \pink{l = 23 \: cm}}}}}}\end{gathered}$

Hence, the length of rectangle is 23 cm.

$\begin{gathered}\end{gathered}$

LEARN MORE :

$\boxed{\begin {minipage}{9cm}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {minipage}}$