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AlladinOne [14]
3 years ago
7

Can you guys answer this

Mathematics
2 answers:
mr_godi [17]3 years ago
6 0
C < 10 would be "The bag contained fewer than 10 carrots"
c > 10 would be "Catherine biked farther than 10 miles"
c < 20 would be "The chair is shorter than 20 in"
c > 20 would be "Carlos scored over 20 points"
Let me know if you have any questions, and I hope this helped!
N76 [4]3 years ago
6 0
First one is The bag contains fewer than 10 carrots.
Second one is Catherine biked farther than 10 miles.
Third one is The Chair is shorter than 20 in.
Fourth one is Carlos scored over 20 points.

Hope this helps :)
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solniwko [45]

Answer:

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3 years ago
How can you estimate 1,506÷2 so that it is close to the actual answer of 753?
Makovka662 [10]
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6 0
3 years ago
Read 2 more answers
A manufacturer uses production method to produce steel rods. A random sample of 17 steel rods resulted in lengths with a standar
Arisa [49]

Answer:

\chi^2 =\frac{17-1}{12.15} 22.09 =15.87

Traditional method

We can find a critical value in the chi square distribution with df =16 who accumulates \alpha/2 =0.05 of the area on each tail and we got:

\chi^2_{crit}= 7.962

\chi^2_{crit}=26.296

Since the calculated value is between the two critical values we don't have enough evidence to conclude that the true deviation is NOT significantly different from 3.5 cm

Confidence level method

We can find the p value like this

p_v =2*P(\chi^2 >15.87)=0.92

Since the p value is higher then the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is NOT significantly different from 3.5 cm

Step-by-step explanation:

Data provided

n=17 represent the sample selected

\alpha=0.1 represent the significance

s^2 =4.7^2 =22.09 represent the sample variance

\sigma^2_0 =3.5^2 =12.15 represent the value to check

Null and alternative hypothesis

We want to verify if the new production method has lengths with a standard deviation different from 3.5 cm, so the system of hypothesis would be:

Null Hypothesis: \sigma^2 = 12.15

Alternative hypothesis: \sigma^2 \neq 12.15

The statistic for this case is given by:

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

The degrees of freedom are:

df =n-1= 17-1=16

\chi^2 =\frac{17-1}{12.15} 22.09 =15.87

Traditional method

We can find a critical value in the chi square distribution with df =16 who accumulates \alpha/2 =0.05 of the area on each tail and we got:

\chi^2_{crit}= 7.962

\chi^2_{crit}=26.296

Since the calculated value is between the two critical values we don't have enough evidence to conclude that the true deviation is significantly different from 3.5 cm

Confidence level method

We can find the p value like this

p_v =2*P(\chi^2 >15.87)=0.92

Since the p value is higher then the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is significantly different from 3.5 cm

7 0
3 years ago
Given: f(x) = X2 - 3 and g(x)= x+1 The composite function g.f is
Minchanka [31]

Answer:

option (c)

Step-by-step explanation:

g.f= g(f(x))

= g(x2 -3)

= (x2 -3)+1

=x2 -2

7 0
3 years ago
Read 2 more answers
Craig used 4 scoops of soil to fill 2/5 of a plant pot. How many scoops will Craig need to fill the whole plant pot?
liberstina [14]

Answer:

10

Step-by-step explanation:

4=2/5 8=4/5 10=5/5

3 0
3 years ago
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