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3 years ago

HELP PLEASE!!! WILL GIVE THANKS & BRAINLIEST

Mathematics

1 answer:

zhuklara [117]3 years ago

7 0

The graph that best represents the system of inequalities would be the second one.

y > -2x - 2

y $\leq$ x + 4

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Assume that in October of a particular year about 215 billion text messages were sent or received in the US, and the prediction

Julli [10]

Answer:

There will be $243$ billion messages sent or received in November.

Step-by-step explanation:

Given.

Number of text messages sent or received $=215$ billion.

Increment on the very next month $=13\%=\frac{13}{100}=0.13$

Lets find what is $13\%\ of\ 215$

⇒ $13\%\ of\ 215$

⇒ $0.13\times 215=27.95$

So we will add this value to our previous months data.

Now

Number of text messages sent in the month of November $=(27.5+215)=242.95$ billion.

Rounding to the nearest tenth the answer will be $243$ billion.

So $243$ billion text messages were sent or received in November.

5 0

3 years ago

. Use the statistical features of your calculator to find the mean and the standard deviation to the nearest tenth of a data set

uysha [10]

Answer:

Mean = 1.9

Standard deviation = 0.6

Step-by-step explanation:

The Mean is calculate by the formula:

$Mean = \frac{\text{Sum of all the observation}}{\text{Total number of observation}}$

⇒ $Mean = \frac{24.9+24.7+24.7+23.4+27.9}{5} = 1.85$

Thus Mean to the nearest tenth is 1.9

Standard Deviation is the square root of sum of square of the distance of observation from the mean.

$Standard deviation(\sigma) = \sqrt{\frac{1}{n}\sum_{i=1}^{n}{(x_{i}-\bar{x})^{2}} }$

where, $\bar{x}$ is mean of the distribution.

Putting all values in the formula, We get

Standard Deviation = 0.597 ≈ 0.6

6 0

3 years ago

6(m-1) = 3(3m + 2) Show all work

nordsb [41]

Answer:

$\boxed{\sf m = -4}$

Step-by-step explanation:

$\sf Solve \: for \: m: \\ \sf \implies 6 (m - 1) = 3 (3 m + 2) \\ \\ \sf Expand \: out \: terms \: of \: the \: left \: hand \: side: \\ \sf \implies 6 m - 6 = 3 (3 m + 2) \\ \\ \sf Expand \: out \: terms \: of \: the \: right \: hand \: side: \\ \sf \implies 6 m - 6 = 9 m + 6 \\ \\ \sf Subtract \: 9 m \: from \: both \: sides: \\ \sf \implies (6 m - 9 m) - 6 = (9 m - 9 m) + 6 \\ \\ \sf 6 m - 9 m = -3 m: \\ \sf \implies -3 m - 6 = (9 m - 9 m) + 6 \\ \\ \sf 9 m - 9 m = 0: \\ \sf \implies -3 m - 6 = 6 \\ \\ \sf Add \: 6 \: to \: both \: sides: \\ \sf \implies (6 - 6) - 3 m = 6 + 6 \\ \\ \sf 6 - 6 = 0: \\ \sf \implies -3 m = 6 + 6 \\ \\ \sf 6 + 6 = 12: \\ \sf \implies -3 m = 12 \\ \\ \sf Divide \: both \: sides \: of \: -3 m = 12 \: by \: -3: \\ \sf \implies \frac{ - 3m}{ - 3} = \frac{12}{ - 3} \\ \\ \sf \frac{ - 3}{ - 3} = 1: \\ \sf \implies m = \frac{12}{ - 3} \\ \\ \sf - \frac{12}{3} = - 4 : \\ \sf \implies m = - 4$