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3 years ago

A line has a slope of 1/7 and passes through the point (14,2). What is its equation in slope-intercept form?

Mathematics

2 answers:

mash [69]3 years ago

8 0

Answer:

y=(1/7)x

Step-by-step explanation:

y= mx+b

m=1/7

to find b:

y=(1/7)x +b

you have point (14,2)-->x=14, y=2

2=(1/7)times14 +b, b=0 ----> y=(1/7)x+0

alekssr [168]3 years ago

5 0

Hope that helps! -Celina

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If sinA=√3-1/2√2,then prove that cos2A=√3/2 prove that

Ivan

Answer:

$\boxed{\sf cos2A =\dfrac{\sqrt3}{2}}$

Step-by-step explanation:

Here we are given that the value of sinA is √3-1/2√2 , and we need to prove that the value of cos2A is √3/2 .

Given :-

• $\sf\implies sinA =\dfrac{\sqrt3-1}{2\sqrt2}$

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• $\sf\implies cos2A =\dfrac{\sqrt3}{2}$

Proof :-

We know that ,

$\sf\implies cos2A = 1 - 2sin^2A$

Therefore , here substituting the value of sinA , we have ,

$\sf\implies cos2A = 1 - 2\bigg( \dfrac{\sqrt3-1}{2\sqrt2}\bigg)^2$

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$\sf\implies cos2A = 1 -2\times \dfrac{ 3 +1-2\sqrt3}{8}$

Add the numbers in numerator ,

$\sf\implies cos2A = 1-2\times \dfrac{4-2\sqrt3}{8}$

Multiply it by 2 ,

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Take out 2 common from the numerator ,

$\sf\implies cos2A = 1-\dfrac{2(2-\sqrt3)}{4}$

Simplify ,

$\sf\implies cos2A = 1 -\dfrac{ 2-\sqrt3}{2}$

Subtract the numbers ,

$\sf\implies cos2A = \dfrac{ 2-2+\sqrt3}{2}$

Simplify,

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3 years ago

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So the Correct answer would be all three of them.
This includes 27:18, 12:8, and 21:14.
The math behind this includes proportions.
For instance, if you multiple 3 by 9, you get 37. You have to multiple 2 by 9 now, and you should get 18. This is how all three of the answers are correct!

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A line has a slope of 1/7 and passes through the point (14,2). What is its equation in slope-intercept form?​

A line has a slope of 1/7 and passes through the point (14,2). What is its equation in slope-intercept form?