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Nezavi [6.7K]
3 years ago
6

Find the value of x so that l is parallel to m

Mathematics
2 answers:
irakobra [83]3 years ago
6 0
3x - 2 + 122 = 180
3x + 120 = 180
3x = 180 - 120
3x = 60
x = 60/3
x = 20 <==
victus00 [196]3 years ago
5 0
The value of x is 48.  
3x-2=122
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Please help ASAP please and thank you have a great and blessed day!
balandron [24]

Answer:

A and C I believe

Step-by-step explanation:

Because when you take 7.429 another nine rounds the 2 and it is higher than 5 so it would make that 7.43 and for C 7.433 the second 3 is lower than 5 so it doesnt change anything, since 5 and above give it a shove and 4 and below let it go, so I believe its A and C

8 0
3 years ago
Find the quotient -7/12 divided by 1/7
leva [86]

Answer:

-4.08

Step-by-step explanation:

4 0
3 years ago
In problems 1-3, a and b are legs and c is the hypotenuse. Find the missing side length of the
Readme [11.4K]

Answer:

1. b=39.497

2. c=3.606

3. a=18.974

Step-by-step explanation:

1.

41^2-11^2=b^2

1681-121=b^2

b^=1560

b=39.497

2.

2^2+3^2=c^2

4+9=c^2

c^2=13

c=3.606

3.

21^2-9^9=a^2

441-81=a^2

a^2=360

a=18.974

4 0
2 years ago
The seventh grade class at a Christian school had 24 students enrolled at the beginning of the school year. At the end of the sc
Darya [45]

Answer:

12.5%

Step-by-step explanation:

27-24=3

3/24=1/8

1/8=0.125

0.125 in percent is 12.5%

7 0
2 years ago
PLEASE HELP
Nookie1986 [14]

For the square with side length n, the diagonal measures:

d = \sqrt{2} *n

<h3>How to get the length of the diagonal?</h3>

The sidelength of the square is n, and we want to get the length of the diagonal d.

Notice that the diagonal is the hypotenuse of a right triangle whose catheti measure n.

Then we can use the Pythagorean theorem, which says that the square of the hypotenuse is equal to the sum of the squares of the cathetus;

d^2 = n^2 + n^2\\\\d^2 = 2n^2\\\\d = \sqrt{2n^2} \\\\d = \sqrt{2}*n

That is the length of the diagonal.

If you want to learn more about right triangles:

brainly.com/question/2217700

#SPJ1

6 0
2 years ago
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