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Taya2010 [7]
3 years ago
5

What is the range of the function below in set builder notation? y=|x-3|

Mathematics
1 answer:
Kisachek [45]3 years ago
4 0

Answer:  \{y | \ y \in \mathbb{R}, \ y \ge 0\}

This translates to "y is any real number such that it is 0 or larger".

The reasoning is that the result of any absolute value function is either 0 or positive. In other words, we'll never get a negative result of an absolute value function. This is due to how absolute value represents distance. Negative distance does not make sense.

So if y = |x-3| then y = 0 is the smallest output possible. We could have any positive output we want.

In terms of a graph (see below), the V shape is at the lowest point (3,0). The y coordinate is all we care about in terms of finding the range. So we see the lowest y value is y = 0.

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3 years ago
Hi i don't get this question in middle school so here it is. Your friend says the product of 4,164 and 137 is 70,460. How will y
agasfer [191]

Answer:

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Step-by-step explanation:

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4 years ago
How do u write 5(2x - 1) in a distributive property
Nookie1986 [14]

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Step-by-step explanation:

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What is the value of -2xy if x = -1 and y= 6?<br> A. 12<br> B. -12<br> C. 26<br> D. 8
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A. 12

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plz mark brainliest

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