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Taya2010 [7]
3 years ago
5

What is the range of the function below in set builder notation? y=|x-3|

Mathematics
1 answer:
Kisachek [45]3 years ago
4 0

Answer:  \{y | \ y \in \mathbb{R}, \ y \ge 0\}

This translates to "y is any real number such that it is 0 or larger".

The reasoning is that the result of any absolute value function is either 0 or positive. In other words, we'll never get a negative result of an absolute value function. This is due to how absolute value represents distance. Negative distance does not make sense.

So if y = |x-3| then y = 0 is the smallest output possible. We could have any positive output we want.

In terms of a graph (see below), the V shape is at the lowest point (3,0). The y coordinate is all we care about in terms of finding the range. So we see the lowest y value is y = 0.

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Answer:

the height of bag b is 7

Step-by-step explanation:

first, find the volume of bag a.

volume formula:

length * width * height = volume

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substitute the values into the formula

4 * 3.5 * 6 = volume

84 = volume

the volume of bag A is 84

next, find the height of bag b

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length * width * height.

length = 8

width = 3

volume = 168 (84 * 2)

8 * 3 * h = 168

24h = 168

24h/24 = 168/24

h = 168/24

h = 7

the height of bag B is 7

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3 years ago
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32

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1/3x96= 31.999

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C is the correct answer



Hope this helps :D
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