Someone help me with this plz

A player of the National Basketball Association’s Portland Trail Blazers is the best free-throw shooter on the team, making 94%

g100num [7]

Answer:

The data for the probabilities are shown in the table below.

- A represents the probability of making the two shots for each of the best and worst shooter on the Portland Trail Blazers' team

- B represents the probability of making at least one shot for each of the best and worst shooter on the Portland Trail Blazers' team.

- C represents the probability of not making any of the two shots for each of the best and worst shooter on the Portland Trail Blazers' team.

N | Best ||| Worst

A | 0.8836 | 0.3136

B | 0.9964 | 0.8064

C | 0.0036 | 0.1936

It becomes evident why fouling the worst shooter on the team is a better tactic. The probabilities of the best shooter making the basket over the range of those two free shots are way better than the chances for the worst shooter.

Step-by-step explanation:

Part 1

Probability of the best shooter of the National Basketball Association’s Portland Trail Blazers making a shot = P(B) = 94% = 0.94

Probability that he doesn't make a shot = P(B') = 1 - 0.94 = 0.06

a) Probability that the best shooter on the team makes the two shots awarded = P(B) × P(B) = 0.94 × 0.94 = 0.8836

b) Probability that the best shooter on the team makes at least one shot.

This is a sum of probabilities that he makes only one shot and that he makes two shots.

Probability that he makes only one shot

= P(B) × P(B') + P(B') + P(B)

= (0.94 × 0.06) + (0.06 × 0.94) = 0.1128

Probability that he makes two shots = 0.8836 (already calculated in part a)

Probability that he makes at least one shot = 0.1128 + 0.8836 = 0.9964

c) Probability that the best shooter on the team makes none of the two shots = P(B') × P(B') = 0.06 × 0.06 = 0.0036

d) If the worst shooter on the team, whose success rate is 56% is now fouled to take the two shots.

Probability of the worst shooter on the team making a shot = P(W) = 56% = 0.56

Probability that the worst shooter on the team misses a shot = P(W') = 1 - 0.56 = 0.44

Part 2

a) Probability that the worst shooter on the team makes the two shots = P(W) × P(W)

= 0.56 × 0.56 = 0.3136

b) Probability that the worst shooter on the team makes at least one shot.

This is a sum of probabilities that he makes only one shot and that he makes two shots.

Probability that he makes only one shot

= P(W) × P(W') + P(W') + P(W)

= (0.56 × 0.44) + (0.44 × 0.56) = 0.4928

Probability that he makes two shots = 0.3136 (already calculated in part a)

Probability that he makes at least one shot = 0.4928 + 0.3136 = 0.8064

c) Probability that the worst shooter makes none of the two shots = P(W') × P(W') = 0.06 × 0.06 = 0.1936

From the probabilities obtained

N | Best ||| Worst

A | 0.8836 | 0.3136

B | 0.9964 | 0.8064

C | 0.0036 | 0.1936

It becomes evident why fouling the worst shooter on the team is a better tactic. The probabilities of the best shooter making the basket over the range of those two free shots are way better than the chances for the worst shooter.

Hope this Helps!!!

8 0

3 years ago

Read 2 more answers

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emmainna [20.7K]

Answer:

x=4/3

Step-by-step explanation:

In pic

(hope this helps can I pls have brainlist (crown) ☺️)

8 0

3 years ago

Read 2 more answers

Solve this simultaneous e<br> x + y = 26<br> 3x + y = 56

trapecia [35]

Answer:

x= 15 and y= 11

Step-by-step explanation:

The goal here is to solve

x + y =26 and

3x + y =56 for the variables x and y.

First, let's work on your first equation, x + y =26

After this initial survey of the equations, the system of equations we'll set out to solve is:

x+y = 26 and 3x+y = 56

Let's start by solving x+y = 26 for the variable x.

Move the y to the right hand side by subtracting y from both sides, like this:

From the left hand side:

y - y = 0

The answer is x

From the right hand side:

The answer is 26-y

Now, the equation reads:

x = 26-y

To isolate the x, we have to divide both sides of the equation by the other variables

around the x on the left side of the equation.

and this is the final solution to your equation.

Next, let's solve 3x+y = 56 for the variable y.

Move the 3x to the right hand side by subtracting 3x from both sides, like this:

From the left hand side:

3x - 3x = 0

The answer is y

From the right hand side:

The answer is 56-3x

Now, the equation reads:

y = 56-3x

To isolate the y, we have to divide both sides of the equation by the other variables

around the y on the left side of the equation.

and this is the final solution to your equation.

Now, plug the earlier result, x=26-y, in for x everywhere it occurs in

y=56-3x.

This gives y=56-3(26-y). Now all we have to do is solve this for y,to have our first solution.

26-y evaluates to 26-y

Multiply 3 by 26-y

we multiply 3 by each term in 26-y term by term.

This is the distributive property of multiplication.

Multiply 3 and 26

1

3 × 26 = 78

Multiply 3 and -y

Multiply 1 and y

The y just gets copied along.

y

3 × -y = -3y

3*(26-y) evaluates to 78-3y

56 - 78 = -22

The answer is -22+3y

56-3*(26-y) evaluates to -22+3y

Move the 3y to the left hand side by subtracting 3y from both sides, like this:

From the left hand side:

y - 3y = -2y

The answer is -2y

From the right hand side:

3y - 3y = 0

The answer is -22

Now, the equation reads:

-2y = -22

To isolate the y, we have to divide both sides of the equation by the other variables

around the y on the left side of the equation.

The last step is to divide both sides of the equation by -2 like this:

To divide y by 1

The y just gets copied along in the numerator.

The answer is y

-2y ÷ -2 = y

-22 ÷ -2 = 11

The solution to your equation is:

y = 11

Lastly, to find the solution for x, we plug this answer for y into the earlier result that

x=26-y.

This gives x=26-(11). Now, simplify this.

26-(11) evaluates to 15

x= 15

So, the solutions to your equations are:

x= 15 and y= 11

3 0

3 years ago

Read 2 more answers

The fourth term of a sequence is 108. Each term after the first is 3 times the previous term. Write an explicit expression that

marishachu [46]

Answer:

$f(n)=4(3)^{n-1}$

Step-by-step explanation:

Let the first term be $x$ , then the terms of the sequence are:

$x,3x,9x,27x,81x,...$ .

Since the fourth term is 108, we have

$27x=108$

$\implies x=4$

Hence the sequence becomes:

$4,12,36,108,324,...$ .

The explicit expression for a geometric expression is given by:

$f(n)=ar^{n-1}$

where a=4 and r=3

The required formula is:

$f(n)=4(3)^{n-1}$

8 0

3 years ago

Please asap I need this for a test

ki77a [65]

Answer:

3

Step-by-step explanation:

(f O g) this basically means that the input x first goes trough the function g and then f. Like f(g(x)).

So when x went trough g, you got the output g(x) and then this went trough f and you got f(g(x)) = -8 = 'f(x)'.

With this in mind you can retrace your steps by first looking at what input can get -8 as an output, for f this is -4. this means g(x) = -4

Then you look at what input (this is the x you're looking for) gets you the ouput -4. Looking at the second image you'll picture see that it's the input 3.

4 0

2 years ago