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3 years ago

Help!!!!

Mathematics

1 answer:

Alexxx [7]3 years ago

8 0

Point B is located at (-2, 5).

In ordered pairs (the point), the x value is first, then the y value is second. Like so: (x,y). According to your question, it is (-2,5). This means the point is left 2 in the x direction, and up 5 in the y direction. This is point B.

I hope this Helps!

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How do I solve these for example 3

Natasha2012 [34]

As the three longitudinal lines are parallel:

angle 4 = 5 = 6 = 82 degree (corresponding angles) = 9 = 8 = 7 = 82 degrees (vertical angles)

and

angle 11 = 180-82= 98 degrees (linear pair)

so:

angle 10 = 11 = 12 = 98 degrees (corresponding angles) = 3 = 2 = 1 = 98 degrees (vertical angles)
.

hope you got it

8 0

3 years ago

If f(n)=(n-1)2+<br><img src="https://tex.z-dn.net/?f=f%28n%29%20%3D%20%28n%20-1%292%20%2B%20%20%20%203n" id="TexFormula1" title=

Liono4ka [1.6K]

Distribute the 2 first.

f(n) = 2n - 2 + 3n

Combine like terms.

f(n) = 5n - 2

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3 years ago

M is the midpoint of AB. A is at (-5, 1) and M is (-1,4). Find the coordinates of B. Select one: O a (-3.2.5) O b.(-1.4) O c. (2

coldgirl [10]

Answer:

A (-3, 2.5)

Step-by-step explanation:

Midpoint formula is m=(x1 + x2/2), (y1 + y2/2)

So add the xs: -5 + -1 = -6

And the ys: 1 + 4 = 5

Then divide them by 2

(-3, 2.5)

4 0

3 years ago

The angle of elevation from me to the top of a hill is 51 degrees. The angle of elevation from me to the top of a tree is 57 deg

julia-pushkina [17]

Answer:

Approximately $101\; \rm ft$ (assuming that the height of the base of the hill is the same as that of the observer.)

Step-by-step explanation:

Refer to the diagram attached.

Let $\rm O$ denote the observer.
Let $\rm A$ denote the top of the tree.
Let $\rm R$ denote the base of the tree.
Let $\rm B$ denote the point where line $\rm AR$ (a vertical line) and the horizontal line going through $\rm O$ meets. $\angle \rm B\hat{A}R = 90^\circ$ .

Angles:

Angle of elevation of the base of the tree as it appears to the observer: $\angle \rm B\hat{O}R = 51^\circ$ .
Angle of elevation of the top of the tree as it appears to the observer: $\angle \rm B\hat{O}A = 57^\circ$ .

Let the length of segment $\rm BR$ (vertical distance between the base of the tree and the base of the hill) be $x\; \rm ft$ .

The question is asking for the length of segment $\rm AB$ . Notice that the length of this segment is $\mathrm{AB} = (x + 20)\; \rm ft$ .

The length of segment $\rm OB$ could be represented in two ways:

In right triangle $\rm \triangle OBR$ as the side adjacent to $\angle \rm B\hat{O}R = 51^\circ$ .
In right triangle $\rm \triangle OBA$ as the side adjacent to $\angle \rm B\hat{O}A = 57^\circ$ .

For example, in right triangle $\rm \triangle OBR$ , the length of the side opposite to $\angle \rm B\hat{O}R = 51^\circ$ is segment $\rm BR$ . The length of that segment is $x\; \rm ft$ .

$\begin{aligned}\tan{\left(\angle\mathrm{B\hat{O}R}\right)} = \frac{\,\rm {BR}\,}{\,\rm {OB}\,} \; \genfrac{}{}{0em}{}{\leftarrow \text{opposite}}{\leftarrow \text{adjacent}}\end{aligned}$ .

Rearrange to find an expression for the length of $\rm OB$ (in $\rm ft$ ) in terms of $x$ :

$\begin{aligned}\mathrm{OB} &= \frac{\mathrm{BR}}{\tan{\left(\angle\mathrm{B\hat{O}R}\right)}} \\ &= \frac{x}{\tan\left(51^\circ\right)}\approx 0.810\, x\end{aligned}$ .

Similarly, in right triangle $\rm \triangle OBA$ :

$\begin{aligned}\mathrm{OB} &= \frac{\mathrm{AB}}{\tan{\left(\angle\mathrm{B\hat{O}A}\right)}} \\ &= \frac{x + 20}{\tan\left(57^\circ\right)}\approx 0.649\, (x + 20)\end{aligned}$ .