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3 years ago

Help!!!!

Mathematics

1 answer:

Alexxx [7]3 years ago

8 0

Point B is located at (-2, 5).

In ordered pairs (the point), the x value is first, then the y value is second. Like so: (x,y). According to your question, it is (-2,5). This means the point is left 2 in the x direction, and up 5 in the y direction. This is point B.

I hope this Helps!

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I need help asap!!!! Please It’s an Algebra 2 question

Elza [17]

Answer:

8) Real; Rational

9) Real; Rational; Integer; Whole; Natural

10) Real; Rational

Step-by-step explanation:

Real numbers consists of the subsets:

Irrational Numbers:

Irrational numbers is the subset complementary to rational numbers. It includes numbers such as √(2) or π. These numbers do not repeat nor terminate.

Rational Numbers:

Rational numbers are all the others. They include the integers as well as the repeating and terminating decimals.

Integers:

Integers include the entire set of whole numbers and the negative numbers. This subset does not include decimals nor fractions. Thus, the integers are: ...-3, -2, -1, 0, 1, 2, 3... etc.

Whole Numbers:

Whole numbers is the set of natural numbers that <em>includes</em> 0. So, whole numbers are: 0, 1, 2, 3... and so on.

Natural Numbers:

Natural numbers or the counting numbers are all the positive, non-decimal numbers. These are 1, 2, 3... and so on. This set does not include 0.

8) $1.\overline{3}=1.3333...$

The given number is not natural, whole, nor an integer because it is a decimal. It repeats, so it belongs to the rational numbers subset.

9) $\sqrt4=2$

The square root of 4 is simply 2. 2 is a natural number. Because of this, this means that 2 is also a whole number, integer, and a rational number.

10) $-3/4=-0.75$

The given number is a fraction and it does not reduce to a whole number, so it's not a natural number, whole number, nor an integer. It does terminate, so it belongs to the rational numbers subset.

7 0

3 years ago

Complete the square to write the quadratic expression in vertex form.

Anvisha [2.4K]

Answer:

1. (x - 3)² = 8

2. (x + 2)² = 3

3. (x + 6)² = $\frac{101}{2}$

4. (x + 3)² = 27

5. (x + 4)² = 13

6. $\bigg( x - \frac{15}{9} \bigg) ^2 = \frac{261}{81} = \frac{29}{9}$

Step-by-step explanation:

Completion of Square: $(x - a) ^2 = x^2 - 2ax + a^2$

In the following problems the terms in the RHS of the above equation may be missing. We balance the equation. Simplify it and re write it in terms of LHS.

1. x² - 6x + 1 = 0

Taking the constant term to the other side, we get:

x² - 6x = - 1

⇒ x² - 2(3)x = -1

⇒ x² -2(3)x + 9 = - 1 + 9 [Adding 9 to both the sides]

⇒ x² -2(3)x + 3² = 8

⇒ (x - 3)² = 8 is the answer.

2. 3x² + 12x + 3 = 0

Note that the co-effecient of x² is not 1. We make it 1, by dividing the whole equation by 3. And then proceed like the previous problem.

3x² + 12x = -3

Dividing by 3 through out, x² + 4x = - 1

⇒ x² + 2(2) + 4 = -1 + 4

⇒ x² +2(2) + 2² = 3

⇒ (x + 2)² = 3 is the answer.

3. 2x² + 24x = 29

x² + 12x = $\frac{29}{2}$

⇒ x² + 2(6)x + 36 = $\frac{29}{2}$ + 36

⇒ x² + 2(6)x + 6² = $\frac{29 + 72}{2}$

⇒ (x + 6)² = $\frac{101}{2}$ is the answer.

4. x² + 6x - 18 = 0

x² + 6x = 18

⇒ x² + 2(3)x = 18

⇒ x² + 2(3)x + 9 = 18 + 9

⇒ x² + 2(3)x + 3² = 27

⇒ (x + 3)² = 27 is the answer.

5. x² + 8x + 3 = 0

x² + 8x = -3

⇒ x² + 2(4)x = -3

⇒ x² + 2(4)x + 16 = - 3 + 16

⇒ x² + 2(4)x + 16 = 13

⇒ (x + 4)² = 13 is the answer.

6. 9x² - 30x + 6 = 0

9x² - 30x = - 6

⇒ x² $- \frac{30}{9}$ x = - 6

$\implies x^2 -2 \bigg( \frac{15}{9} \bigg )x + \frac{225}{81} = - 6 + \frac{225}{81}$

$\implies x^2 - 2\bigg( \frac{15}{9} \bigg ) x + \bigg ( \frac{15}{9} \bigg ) ^2 = \frac{261}{81}$

$\bigg( x - \frac{15}{9} \bigg) ^2 = \frac{261}{81} = \frac{29}{9}$ is the answer.

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3 years ago

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daser333 [38]

Minus 9 from both sides

7x = 49

X = 7

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3 years ago

Long division (3a²-8a? +19a – 7) + (3a-2)

myrzilka [38]

Answer:

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Step-by-step explanation:

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