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3 years ago

If you can answer all of them that would mean a lot,

Mathematics

2 answers:

SCORPION-xisa [38]3 years ago

7 0

Answer:

oh ur up at night.. me to...

Step-by-step explanation:

sveta [45]3 years ago

6 0

1. 15
2. 17
3. 15
4. 9
5. √125

Hope this helps :)

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Suppose in the University of Manitoba, 40% of the students live in apartments. If 600 students are randomly selected, then the a

just olya [345]

Answer:

$P(200\leq X\leq 400)=P(\frac{200-240}{12}\leq \frac{X-\mu}{\sigma}\leq \frac{400-240}{12})=P(-3.33\leq Z \leq 13.33)$

$=P(Z$

So then the correct answer would be:

B) .9996

Step-by-step explanation:

The exact way to solve this problem is using the binomial distribution, assuming that our random variable of interest is "number of students living in apartments" represented by X and $X \sim Bin(n=600, p =0.4)$

And we want this probability:

$P(200 \leq X \leq 400) [tex]In order to find this probability we can use the foloowing excel code:"=BINOM.DIST(400,600,0.4,TRUE)-BINOM.DIST(199,600,0.4,TRUE)"And we got:[tex] P(200 \leq X \leq 400) =0.999675[tex]But for this case the problem says that we need to approximate, so then we can use the normal approximation to the normal distribution. We need to check the conditions in order to use the normal approximation.
[tex]np=600*0.4=240\geq 10$

$n(1-p)=600*(1-0.4)=360 \geq 10$

So we see that we satisfy the conditions and then we can apply the approximation.

If we appply the approximation the new mean and standard deviation are:

$E(X)=np=600*0.4=240$

$\sigma=\sqrt{np(1-p)}=\sqrt{600*0.4(1-0.4)}=12$

And then $X \sim N (\mu = 240, \sigma= 12)$

And we are interested on the following probability:

$P(200\leq X\leq 400)=P(\frac{200-240}{12}\leq \frac{X-\mu}{\sigma}\leq \frac{400-240}{12})=P(-3.33\leq Z \leq 13.33)$

$=P(Z$

So then the correct answer would be:

B) .9996

6 0

3 years ago

HELP<br> what is the value of “ c”

Alex

Answer:

Step-by-step explanation:

When you match the form

... ax² + bx + c = 0

to the equation

... 3x² + 5x + 7 = 0

it is reasonable to conclude that ...

... a = 3, b = 5, c = 7.

_____

The question presumes you are familiar with the form

... ax² +bx +c = 0

which is often used as the representation of a general quadratic equation. This lets us use a, b, and c instead of specific numbers, to talk about ways of factoring, graphing, or solving equations like this.

6 0

4 years ago

The First Lady planted rhubarb in the square bed above. Express the perimeter of the rhubarb bed in the terms of x.

weeeeeb [17]

Answer:

......

Step-by-step explanation:

7 0

3 years ago

Solve the system of equations. x + 3y = −1 2x + 2y = 6

mihalych1998 [28]

1x+ 3y = -12x + 2y = 6
+12x +12x
13x + 3y = 2y = 6
+3y +3y
13x = 5y = 6
13x = 5y and 5y = 6