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Answer:
8
Step-by-step explanation:
Since they intersect you can just solve for x and y
since y=-4x and y=x^2+2x+8, you can set -4x=x^2+2x+8
add 4x to both sides to make 0=x^2+6x+8
and factor out (x+4)(x+2)
so the solutions for x are -4 and -2
then insert the two values for x into the first equation
so y=-4(-4) and y=-4(-2)
so y=16 and y=8 when x=-4 and x=-2
so the smallest value for y in both equations is 8
Please give brainliest :)
Hello,
If center is (0,0)
x²/a²+y²/b²=1 for a half horizontal axis of a, and a half vertical axis of b
Here
a=2 ==> a²=4
b=8 ==> b²=64
Answer:c
Step-by-step explanation:none of these are good answers as they can all exist in flat Euclidean space. The best answer is c because a great circle exists in spherical (non-flat) geometry . However it’s not really correct to say you could never describe a great circle in Euclidean space and whoever wrote this question (not you, the original author of the question) deserves to bite their tongue on their dinner tonight
Being able to write fractions in simplest form can make operations much easier. Also, to compare fractions, some may have to be in the simplest form.