All you have to do is multiply 4 × 6 to get your answer. So, 4 × 6 = 24, and considering we can't leave the variable out, we have to put it with our answer. Our answer is then 24x. Hint: Parentheses mean multiplication.
Supplements add up to 180°
so just subtract 164 from 180
180
<u>-164
</u> 16
Answer:
a rectangle is twice as long as it is wide . if both its dimensions are increased 4 m , its area is increaed by 88 m squared make a sketch and find its original dimensions of the original rectangle
Step-by-step explanation:
Let l = the original length of the original rectangle
Let w = the original width of the original rectangle
From the description of the problem, we can construct the following two equations
l=2*w (Equation #1)
(l+4)*(w+4)=l*w+88 (Equation #2)
Substitute equation #1 into equation #2
(2w+4)*(w+4)=(2w*w)+88
2w^2+4w+8w+16=2w^2+88
collect like terms on the same side of the equation
2w^2+2w^2 +12w+16-88=0
4w^2+12w-72=0
Since 4 is afactor of each term, divide both sides of the equation by 4
w^2+3w-18=0
The quadratic equation can be factored into (w+6)*(w-3)=0
Therefore w=-6 or w=3
w=-6 can be rejected because the length of a rectangle can't be negative so
w=3 and from equation #1 l=2*w=2*3=6
I hope that this helps. The difficult part of the problem probably was to construct equation #1 and to factor the equation after performing all of the arithmetic operations.
Answer:
12√3 inches or 20.785 inches.
Step-by-step explanation:
A regular hexagon can be defined as a polygon with 6 sides.
The formula for the perimeter of a regular hexagon =
6 × the length of the sides of the hexagon.
From the above question, we are told that there is an inscribed circle I'm the hexagon with a diameter of 4√3 inches long
Step 1
Find the radius of the circle
Radius of the circle = 4√3/2 = 2√3 inches
Step 2
The radius of the inscribed circle = Length of one of the sides of a regular hexagon.
Hence, the perimeter of the regular hexagon = 6 × 2√3
= 12√3 inches
= 20.784609691 inches.
Approximately 20.785 inches
Don’t really pay attention to the x .