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omeli [17]
3 years ago
15

A pilot traveling 175 miles per hour encounters a head wind of 35 knots. If there are 1.15 knots per mph, what will her true spe

ed be in miles per hour? (Round to the nearest mph.)
Mathematics
1 answer:
KonstantinChe [14]3 years ago
3 0
Since one knot is 1.15 mph.
We multiply 35 time 1.15, which equals 40.25 mph.
Then we subtract. 175 - 4.25 = 134.75
Round, and you'll get 135mph
Therefore, your answer is 135mph
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At the store the ratio of books sold to movies sold was 8:2. For every __ books sold there were __ movies sold
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8:2

divide  each side by 2

4:1

For every _8_ books sold there were _2_ movies sold  OR

For every _4_ books sold there were _1_ movies sold

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(0,-2)

(2,-1)

(4,0)

Step-by-step explanation:

The points are the above ones.

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mash [69]

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The lowest point is -100 meters, or 100 meters down

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7 0
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The FBI wants to determine the effectiveness of their 10 Most Wanted list. To do so, they need to find out the fraction of peopl
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<em>98% of confidence intervals for the Population proportion of people who captured after appearing on the 10 most wanted list</em>

(0.3583 , 0.4579)

Step-by-step explanation:

<u>Explanation</u>:-

<em>Given sample size 'n' = 517</em>

Given data Suppose a sample of 517 suspected criminals is drawn. Of these people, 211 were captured.

'x' =211

<em>The sample proportion</em>

                                   p^{-}  = \frac{x}{n} = \frac{211}{517} =0.4081

                                  q^{-} = 1-p^{-} = 1- 0.4081 = 0.5919

<em>98% of confidence intervals for the Population proportion of people who captured after appearing on the 10 most wanted list</em>

(p^{-}  - Z_{\frac{\alpha }{2}  } \sqrt{\frac{p^{-} (1-p^{-} )}{n} } , p^{-} + Z_{\frac{\alpha }{2} } \sqrt{\frac{p^{-} (1-p^{-} }{n} } )

(0.4081  - 2.326   \sqrt{\frac{0.4081 (0.5919 )}{517} } , 0.4081+ 2.326\sqrt{\frac{0.4081(0.5919 }{517} } )

(0.4081-0.0498 , 0.4081 +0.0498)

(0.3583 , 0.4579)

<u><em>Conclusion</em></u>:-

<em>98% of confidence intervals for the Population proportion of people who captured after appearing on the 10 most wanted list</em>

(0.3583 , 0.4579)

7 0
4 years ago
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