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OLEGan [10]
3 years ago
12

Two fifths of d is subtracted from 7

Mathematics
1 answer:
Schach [20]3 years ago
3 0

Answer:

See Below

Step-by-step explanation:

\frac{2}{5} -7

First, let's make 7 into an improper fraction

7x5 =35

2/5 - 35/5 = -33/5

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Enter the value for x that makes an equation 16= -4(x-1) +4 true
lions [1.4K]

Answer:

-2

Step-by-step explanation:

16= -4(x-1)+4

16 - 4 = -4x + 4

12 = -4x + 4

12 - 4 = -4x

8 = -4x

x = 8 ÷ -4

x = -2

6 0
4 years ago
A searchlight is shaped like a parabola. If the light source is located 3 feet from the base along the axis of symmetry and the
Elis [28]

9514 1404 393

Answer:

  8√3 ≈ 13.86 ft

Step-by-step explanation:

The light source is usually placed at the focus, so the focus-vertex distance is p=3 ft. The equation for the parabola with its vertex at the origin is ...

  y = 1/(4p)x^2

  y = 1/12x^2

The opening for some y-value extends ±x from the axis of symmetry, so is a total of 2x in width.

For y=4, the corresponding value of x is ...

  4 = 1/12x^2

  48 = x^2

  √48 = x = 4√3

Then the width of the searchlight opening is ...

  2(4√3 ft) = 8√3 ft ≈ 13.86 ft

5 0
3 years ago
The length of a rectangle is (x + 2). The
Oksanka [162]

Answer:

a

Step-by-step explanation:

7 0
4 years ago
Help answer please!!!!
MAVERICK [17]

Answer:

QR ≈ 16.2 ft

Step-by-step explanation:

Using the tangent ratio in the right triangle.

tan62° = \frac{opposite}{adjacent} = \frac{QR}{RP} = \frac{QR}{8.6} ( multiply both sides by 8.6 )

8.6 × tan62° = QR , then

QR ≈ 16.2 ft ( to the nearest tenth )

5 0
3 years ago
Y>1 and y>x on a graph
zlopas [31]

So,

y>1\wedge y>x

1. Graph each inequality separately.

2. Choose a test point to determine which side of the line needs to be shaded.

3. The solution to the system will be the area where the shadings from each inequality overlap one another (purple area)

As for the system of inequalities we say it's unbounded.

3 0
3 years ago
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