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lesya692 [45]
3 years ago
5

What is the domain of the finction f(x)= x^s

Mathematics
1 answer:
Drupady [299]3 years ago
5 0

Answer:

undefined

Step-by-step explanation:

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Find the sum of (1-1/n) + (1-2/n) + (1 - 3/n)....upto n terms
bija089 [108]

Answer:

<em> (n - 1)/2</em>

Step-by-step explanation:

F = (1 - 1/n) + (1 - 2/n) + (1 - 3/n) + ...(1 - n/n)

  = (1 + 1 ... + 1) - (1/n + 2/n + 3/n + ...n/n)

     (there are n terms of 1)

  = n - (1 + 2 + 3 + ... + n)/n

  = n - [n x (n + 1)/2]/n

  = n - [n x (n + 1)]/[2 x n]

  = n - (n+1)/2

  = (2n - n - 1)/2

  = (n - 1)/2

Hope this helps!

4 0
3 years ago
What is 5 ÷ 1/5 <br> I really need help with dividing whole numbers by fractions
salantis [7]

Answer:

25

Step-by-step explanation:

When dividing by fractions, you can multiply by the opposite reciprocal.

5 ÷ 1/5

5 x 5/1

25

4 0
3 years ago
Read 2 more answers
Which of the points satisfy the linear inequality graphed here?
SOVA2 [1]
Only
<span>c) (-10,0)
because that is the only point in the shaded region.
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3 years ago
Find the negation of the proposition
murzikaleks [220]

In accordance with <em>propositional</em> logic, <em>quantifier</em> theory and definitions of <em>simple</em> and <em>composite</em> propositions, the negation of a implication has the following equivalence:

\neg (\exists \,x\, (P(x) \implies  Q(x))) \iff \forall \,x (\neg \,Q(x) \,\land \,P(x)) (Correct choice: iii)

<h3>How to find the equivalent form of a proposition</h3>

Herein we have a <em>composite</em> proposition, that is, the union of <em>monary</em> and <em>binary</em> operators and <em>simple</em> propositions. According to <em>propositional</em> logic and <em>quantifier</em> theory, the negation of an implication is equivalent to:

\neg (\exists \,x\, (P(x) \implies  Q(x))) \iff \forall \,x (\neg \,Q(x) \,\land \,P(x))

To learn more on propositions: brainly.com/question/14789062

#SPJ1

8 0
2 years ago
If you solve an equation and get an answer like x=-4, how many solutions does it have?
Furkat [3]
The answer would be it has one solution
6 0
3 years ago
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