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LiRa [457]
3 years ago
12

Seventeen less than a number is negative two. What is that number?

Mathematics
2 answers:
Pie3 years ago
8 0

Answer:

15

Step-by-step explanation:

15

marta [7]3 years ago
5 0

Answer:15

Step-by-step explanation:

15-17=-2

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What are the zeros of the polynomial equation f(x)=x^2-12x+20?
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f(x)=x^2-12x+20\\\\\text{The zeros:}\\\\f(x)=0\to x^2-12x+20=0\\\\x^2-10x-2x+20=0\\\\x(x-10)-2(x-10)=0\\\\(x-10)(x-2)=0\iff x-10=0\ \vee\ x-2=0\\\\\boxed{x=10\ \vee\ x=2}
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All sets that contain the number 5 ?
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Real numbers, rational numbers, Integers, Whole numbers, and Natural numbers. 
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Specific gravity will tell you a fraction of how much
Nikolay [14]

The value 0.92 indicates the relative density of the ice.

Data;

  • Density = 0.92g/ml
  • Specific gravity = 0.92

<h3>Specific Gravity</h3>

Specific gravity of a substance is defined as the relative density of substance. This can be further said to be the ratio between the density of a substance to the density of the reference substance.

mathematically;

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The value 0.92 indicates the relative density of the ice.

Learn more on specific gravity here;

brainly.com/question/14932758

3 0
2 years ago
Suppose an object is launched from ground level directly upward at 57.4 f/s Write a function to represent the object’s height ov
Semmy [17]

Answer: p(t) = (-16 ft/s^2)*t^2 + (57.4 ft/s)*t

Step-by-step explanation:

We can suppose that the only force acting on the object is the gravitational force, then the acceleration of the object will be equal to the gravitational acceleration.

Then we can write:

a(t) = -32 ft/s^2

Where the negative sign is because this acceleration is downwards.

Now, to get the vertical velocity of the object, we need to integrate over time to get:

v(t) = (-32 ft/s^2)*t + v0

where t represents time in seconds and v0 is the constant of integration, and in this case, is the initial vertical velocity.

In this case, the initial velocity is 57.4 ft/s upwards, then the velocity equation is:

v(t) = (-32 ft/s^2)*t + 57.4 ft/s

To get the position equation we need to integrate over time again, to get:

p(t) = (1/2)*(-32 ft/s^2)*t^2 + (57.4 ft/s)*t + p0

Where p0 is the initial height of the object, as it was launched from the ground, then the initial position is p0 = 0ft.

then the position equation (that is the function that represents the height of the object as a function over time) is:

p(t) = (1/2)*(-32 ft/s^2)*t^2 + (57.4 ft/s)*t

p(t) = (-16 ft/s^2)*t^2 + (57.4 ft/s)*t

3 0
3 years ago
Write 46,056 in expanded form
kakasveta [241]
Fourty six thousand and fifty six. In expanded form it'll look like this:

40,000
6,000
0
50
6
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