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Crazy boy [7]
3 years ago
11

Combien de morceaux de 15cm peut on découper dans une ficelle de 1cm ?​

Mathematics
1 answer:
poizon [28]3 years ago
7 0

Answer:

English translate for my help please??!

Step-by-step explanation:

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Take a factor out of the square root:
Nat2105 [25]

Answer:

See below.

Step-by-step explanation:

Lets take √72:

Factoring 72 to find perfect squares:

72 = 2*2*2*3*3

The largest perfect square in the above = 2*2*3*3 = 36.

So we can write 72 as 36*2.

√72 = √(36 * 2)

√36 * √2

= 6√2.

One more example:

√18  = √(2*3*3)

= √9*√2

= 3√2.

6 0
3 years ago
What's 3 and 2 5ths plus 1 and 1 5ths
navik [9.2K]
3 and 2/5 turns into 17/5
1 and 1/5 turns into 6/5
17+6= 23
23/5 simplifies to 4 and 3/5
6 0
3 years ago
Read 2 more answers
2a+3/2 - a-2/3 = a-1/4
lesya [120]

Answer:

No solutions

Step-by-step explanation:

2a+\dfrac{3}{2}-a-\dfrac{2}{3}=a-\dfrac{1}{4}\\a+\dfrac{5}{9}=a-\dfrac{1}{4}\\\dfrac{5}{9}=\dfrac{1}{4}

This equation has no solutions. Hope this helps!

7 0
3 years ago
Read 2 more answers
You can rake a 20 square meter lawn in 10 minutes. If your mother asks you to rake your own lawn, which is 30 square meters, how
arsen [322]
20 square meter lawn..............................10 min
10 square meter lawn...............................5 min
30 square meter lawn in.........................5*3=15 min
5 0
3 years ago
3. The backyard of a home is a rectangle 25m by 30m. A garden of uniform width is to be
KiRa [710]

Answer:

Part A

The width of the garden is approximately 3.987 meters

Part B

Please find attached the drawing of the solution

Step-by-step explanation:

Part A

The given parameters are;

The dimensions of the backyard of the home = 25 m by 30 m

The width of the garden to be built in the yard = Uniform width

The shape of the grass left inside = Rectangular

The area of the grass at the center = The area of the garden

Let 'x' represent the width of the garden, we have;

The length of the rectangular grass area at the center, l = 30 - 2·x

The width of the rectangular area of grass at the center, w = 25 - 2·x

The area of the rectangular backyard, A = 30 m × 25 m = 750 m²

The area of the rectangular backyard, A = (The area of the garden) + (The area of the rectangle of grass inside)

The area of the rectangle of grass, GA = (30 - 2·x)·(25 - 2·x) = The area of the garden

The area of the rectangular backyard, A = 750 = (30 - 2·x)·(25 - 2·x) + (30 - 2·x)·(25 - 2·x)  = 2 × (30 - 2·x)·(25 - 2·x) = 8·x² - 220·x + 1,500

∴ 750 = 8·x² - 220·x + 1,500

8·x² - 220·x + 1,500 - 750 = 0

8·x² - 220·x + 750 = 0

x = (220 ± √(220² - 4 × 8 × 750))/(2 × 8)

x ≈ 23.513, or x = 3.987

When x = 25.513, the width of the rectangle of grass inside, w = 25 - 2 × 23.513 = -22.026, which is not a natural (physically possible)

Therefore, the possible width of the garden, x ≈ 3.987

Part B

The drawing of the solution created with MS Visio is attached

6 0
3 years ago
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