Please answer this correctly

Mathematics

2 answers:

Brut [27]3 years ago

7 0

Idk I’m just doing it for I could finish The login sorry

Over [174]3 years ago

7 0

<h3>Answer: 6</h3>

Mark all of the values that are between 61 and 80. See the diagram below. You should mark exactly 6 values.

You might be interested in

Please help! I do not understand. Letter b) cannot be the answer

ivanzaharov [21]

If he has 1/4 of a cup, that means he must fill it up 4 times to equal 1 cup (1/4*4). if he wants 2 cups he must fill it up 8 times.

3 0

3 years ago

The line with equation −a+3b=0 coincides with the terminal side of an angle θ in standard position and sinθ<0 .

Anna11 [10]

If $a$ is the variable of the horizontal axis, then you can solve for $b$ to get the equation of the line in slope-intercept form in the $a,b$ plane:

$-a+3b=0\implies b=\dfrac a3$

i.e. a line with slope $\dfrac13$ through the origin, which means it is contained in the first and third quadrants. Since the terminal side of $\theta$ has a negative sine, the angle must lie in the third quadrant.

Because the slope of the line is $\dfrac13$ , you can choose any length along the line to make up the hypotenuse of a right triangle with reference angle $\theta$ . Any such right triangle will have $\tan\theta=\dfrac13$ , regardless of whether the angle is the first or third quadrant. But since $\theta$ is known to lie in the third quadrant, and so $\sin\theta$ and $\cos\theta$ are both negative, you have

$\tan\theta=\dfrac{\sin\theta}{\cos\theta}=\dfrac13\implies \dfrac{\sin\theta}{\cos\theta}=\dfrac{-1}{-3}\implies \cos\theta=-3$