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GREYUIT [131]
3 years ago
9

I am thinking of an a number less than 20 greater than 10. the sum of the digits in the number is 6. what is the number? It’s fo

r a game I’m playing
Mathematics
1 answer:
Leno4ka [110]3 years ago
3 0

Answer:

might be 12

Step-by-step explanation:

i think so its prob 12 i just have a feeling

You might be interested in
The height of a triangle is 5 cm shorter than its base. If the area of the triangle is 25 cm2, find the height of the triangle.
Olin [163]

Answer:

h = 5\ cm

Step-by-step explanation:

Let's call B at the base of the triangle and call h at the height of the triangle. Then we know that:

The height of a triangle is 5 cm shorter than its base. This means that:

h = B-5.

 The area of the triangle is 25 cm²

By definition the area of a triangle is:

A = 0.5Bh

For this triangle we know that A = 25\ cm^2 and h = B-5. We substitute these values in the equation and solve for B.

25 = 0.5B (B-5)

0.5B ^ 2-\frac{5}{2}B-25 = 0

Now we use the quadratic formula to solve the equation.

For an equation of the form ax ^ 2 + bx + c = 0 the quadratic formula is:

B=\frac{-b\±\sqrt{b^2-4ac}}{2a}

In this case note that:  a=0.5,\ \ b=-\frac{5}{2}\ \ c=-25

Then:

B=\frac{-(-\frac{5}{2})\±\sqrt{(-\frac{5}{2})^2-4(0.5)(-25)}}{2(0.5)}

B=\frac{\frac{5}{2}\±\sqrt{\frac{25}{4}+50}}{1}

B=\frac{5}{2}\±\frac{15}{2}

The solutions are:

B_1=\frac{5}{2}+\frac{15}{2}=10

B_2=\frac{5}{2}-\frac{15}{2}=-5

For this problem we take the positive solution.

B=10\ cm

Now we substitute the value of B in the equation to find the height h

h = 10-5

h = 5\ cm

6 0
3 years ago
Rationalise the denominator of: (√3 + √2)/(√3-√2) = ?<br>​
krok68 [10]

Step-by-step explanation:

<h3><u>Given</u><u>:</u><u>-</u></h3>

(√3+√2)/(√3-√2)

<h3><u>To </u><u>find</u><u>:</u><u>-</u></h3>

<u>Rationalised</u><u> form</u><u> </u><u>=</u><u> </u><u>?</u>

<h3><u>Solution</u><u>:</u><u>-</u></h3>

We have,

(√3+√2)/(√3-√2)

The denominator = √3-√2

The Rationalising factor of √3-√2 is √3+√2

On Rationalising the denominator then

=>[(√3+√2)/(√3-√2)]×[(√3+√2)/(√3+√2)]

=>[(√3+√2)(√3+√2)]×[(√3-√2)(√3+√2)]

=>(√3+√2)²/[(√3-√2)(√3+√2)]

=> (√3+√2)²/[(√3)²-(√2)²]

Since (a+b)(a-b) = a²-b²

Where , a = √3 and b = √2

=> (√3+√2)²/(3-2)

=> (√3-√2)²/1

=> (√3+√2)²

=> (√3)²+2(√3)(√2)+(√2)²

Since , (a+b)² = a²+2ab+b²

Where , a = √3 and b = √2

=> 3+2√6+2

=> 5+2√6

<h3><u>Answer:-</u></h3>

The rationalised form of (√3+√2)/(√3-√2) is 3+2√6+2.

<h3><u>Used formulae:-</u></h3>

→ (a+b)² = a²+2ab+b²

→ (a-b)² = a²-2ab+b²

→ (a+b)(a-b) = a²-b²

→ The Rationalising factor of √a-√b is √a+√b

8 0
3 years ago
Why is not reasonable to say that 4.23 is less than 4.135
AysviL [449]

Simply because 4.135 is a larger number than 4.23.

8 0
3 years ago
At the end of 10 basketball games, a teams mean score is 35 points per game. At the end of 11 games, their mean score has gone d
morpeh [17]

Their total points for the first 10 games were

(10) x (35) = 350 total .

Their total points after 11 games were

(11) x (33) = 363 total .

They must have scored (363 - 350) = 13 points in that 11th game.

I hate to say it, but these kids and their coach are in the wrong game.

4 0
3 years ago
The second question
stich3 [128]

2)

A: 5

B: 9a & a (from a/6)

C: -5 & ÷4

D: -5 & 9a

I haven't done algebra in a year, so don't think my answers are perfect!

definitions:

term: something separated by a sign/symbol (÷, ×, - +) (a/6 are two separate terms, ÷)

constant terms: variables that can be solved.

unlike terms: terms that don't "go" together, you can't subtract 5 from 9a because there's a variable in the way (eyy that rhymes)

like terms: terms that you can add/subtract/multiply/divide to another term

(another answer to c is 9a & a)

7 0
4 years ago
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