Answer:
a)
And we can find this probability with this difference:
And using the norma standard distribution or excel we got:
b) ![P(X>6) =P(Z> \frac{6-7.37}{1.25}) = P(Z>-1.096)](https://tex.z-dn.net/?f=P%28X%3E6%29%20%3DP%28Z%3E%20%5Cfrac%7B6-7.37%7D%7B1.25%7D%29%20%3D%20P%28Z%3E-1.096%29)
And using the complement rule we got:
![P(Z>-1.096) =1-P(Z](https://tex.z-dn.net/?f=P%28Z%3E-1.096%29%20%3D1-P%28Z%3C-1.096%29%20%3D%201-0.137%3D%200.863)
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Part a
Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:
Where
and
We are interested on this probability
And the best way to solve this problem is using the normal standard distribution and the z score given by:
If we apply this formula to our probability we got this:
And we can find this probability with this difference:
And using the norma standard distribution or excel we got:
Part b
For this case we want this probability:
![P(X>6)](https://tex.z-dn.net/?f=%20P%28X%3E6%29)
And we can use the z score and we got:
![P(X>6) =P(Z> \frac{6-7.37}{1.25}) = P(Z>-1.096)](https://tex.z-dn.net/?f=P%28X%3E6%29%20%3DP%28Z%3E%20%5Cfrac%7B6-7.37%7D%7B1.25%7D%29%20%3D%20P%28Z%3E-1.096%29)
And using the complement rule we got:
![P(Z>-1.096) =1-P(Z](https://tex.z-dn.net/?f=P%28Z%3E-1.096%29%20%3D1-P%28Z%3C-1.096%29%20%3D%201-0.137%3D%200.863)