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Alinara [238K]
3 years ago
7

Please help!! I need to know this by today

Mathematics
2 answers:
DiKsa [7]3 years ago
6 0
The answer is 94.2 cm. multiply 3.14*10*6 divide 2.

liraira [26]3 years ago
6 0
So to find out the surface area of the bottom of the pencil holder, we can use the formula for the area of a circle.

A(bottom)=πr²
plug in the data we know
A(bottom)=π6²
A(bottom)=π*36
A(bottom)=36π cm²

For the surface area of the side, we need to find out the circumference of the bottom circle and then multiply that by the height.

A(side)=C*h

C=πd
C=π12
C=12π

A(side)=12π*10
A(side)=120π cm²

Total surface area=36π+120π=156π or 490.09cm²
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Step-by-step explanation:

25 percent of 280 is 70 so it is 350

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Find a fraction equivalent to 5/7 whose squared terms add up to 1184.
bogdanovich [222]

The system of equations of two unknowns is formulated and solved.

\large\displaystyle\text{$\begin{gathered}\sf \bf{ \left\{\begin{matrix} \ \ \ \dfrac{x}{y} = \dfrac{5}{7} \\ x^2+y^2 = 1184 \end{matrix}\right. \ \Longrightarrow \ x=\dfrac{5}{7}y  } \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf \bf{ \left (\dfrac{5}{7}y \right )^2+y^2=1184\ \Longrightarrow\ 25y^2+49y^2=58016 } \end{gathered}$}

                                                              \large\displaystyle\text{$\begin{gathered}\sf \bf{74y^{2}=58016} \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf \bf{ \ \  \ \ \ \ y^{2}=784 } \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf \bf{ \ \ \ \ \ y=\pm\sqrt{784}=\pm28  } \end{gathered}$}

                                                                  \large\displaystyle\text{$\begin{gathered}\sf \bf{ x=\dfrac{5}{7}(\pm 28)=\pm 20  } \end{gathered}$}

The fraction that satisfies the request is \bf{\dfrac{20}{28}} , since in \bf{\dfrac{-20}{-28}} the negative signs are canceled and the first fraction is obtained.

3 0
1 year ago
What base-ten number is 14 tens and 4 ones?¿
MrMuchimi

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Step-by-step explanation:


7 0
3 years ago
What are the first 3 terms in. t(n)=-2n+7
seropon [69]

Answer:

The first 3 terms of the sequence t(n)=-2n+7 are:

5, 3, 1

Step-by-step explanation:

Given the sequence

t(n)=-2n+7

Here n represents any term number in the sequence

Determining the first term

substitute n = 1 in the sequence to determine the first term

t(n)=-2n+7

t(1)=-2(1)+7

t(1)=-2+7

t(1) = 5

Determining the 2nd term

substitute n = 2 in the sequence to determine the 2nd term

t(n)=-2n+7

t(2) = -2(2) + 7

t(2) = -4 + 7

t(2) = 3

Determining the 3rd term

substitute n = 3 in the sequence to determine the 3rd term

t(n)=-2n+7

t(3) = -2(3) + 7

t(3) = -6 + 7

t(3) = 1

Therefore, the first 3 terms of the sequence t(n)=-2n+7 are:

5, 3, 1

5 0
3 years ago
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